Running Coverity on my code results in tainted string error message. I am using the "path" variable declared in the stack, so I am not sure why I am seeing errors. I can only think that using getenv()
directly in the strncpy()
is causing the error. Would the fix below eliminate this error?
char path[1024] = {NULL, };
if(getenv("A"))
strncpy(path, getenv("A"), strlen(getenv("A")));
to
char path[1024] = {NULL, };
char * adriver = getenv("A");
if(adriver)
strncpy(path, adriver, strlen(adriver));
Judging from Tainted string in C , it seems Coverity is a bit extreme about tainted strings. While the warning you get indicates a real problem, getting rid of the warning may sometimes require strange workarounds.
In this, a tainted data source is a location in the program where data is being read from a risky source. For instance, in C, a call to the function getenv (). A tainted data sink is a location to which tainted data should not flow, unless it has been checked for validity.
I am not sure Coverity diagnoses the problem correctly, you did not post the exact error message. Coverity is possibly indicating that you use a string from the environment, that could have any length, potentially causing a buffer overflow when copied by your code into a 1024 byte buffer, indeed it is a good thing it pointed you to this.
An example of a poor place to input tainted data would be to the function strcpy (). However, once a value has been checked, it is said to have been cleansed and no longer tainted. Tainted data vulnerabilities should always be a concern for developers.
No, this will probably not fix the error.
Coverity is telling you that the data within environment variable "A" could be pretty much anything; this data is not under the control of your program.
Therefore, you need to have some sanity checks on the data before you use it.
Your proposed fix will currently have a buffer overflow, if somebody sets environment variable A to a string containing 1025 characters.
Additionally, neither version of code will ever NUL-terminate the "path" string. This is because, you are using strncpy, which will not NUL-terminate if the byte limit is applied (which it will in this case, because you say "limit the copied string to the length I just got from the string").
What you should be doing, is size-check the string first. If it is too large, return some sort of error code; the path in variable A is too big, so your code will not function as desired. If it is not too large, copy it into the path buffer. If you want to use strncpy, make sure to leave room for a NUL at the end, and then explicitly add it, since strncpy is not guaranteed to put a NUL there.
Your code is incorrect: you have a potential buffer overflow in both alternatives.
I am not sure Coverity diagnoses the problem correctly, you did not post the exact error message. Coverity is possibly indicating that you use a string from the environment, that could have any length, potentially causing a buffer overflow when copied by your code into a 1024 byte buffer, indeed it is a good thing it pointed you to this. Here is why:
strncpy
does not do what you think it does. This function should never be used, its semantics are error prone, it is not the right tool for your purpose. strncpy(dest, src, n)
copies no more than n
chars from src
to dest
and fills the rest of the array at dest
with '\0'
bytes until n
bytes have been written. dest
must point to an array of at least n
chars. If src
is shorter, the behavior is inefficient as the padding is usually unnecessary, but if src
has a length of at least n
, dest
will not be null terminated by strncpy
, leading to undefined behavior in many cases.
Your code:
char path[1024] = { NULL, };
if (getenv("A"))
strncpy(path, getenv("A"), strlen(getenv("A")));
is equivalent to
char path[1024] = { NULL, };
if (getenv("A"))
memcpy(path, getenv("A"), strlen(getenv("A")));
As you see, no real protection is granted.
You call getenv
3 times, it would indeed be more efficient to use your alternative implementation, but there are other problems:
You initialize path
with { NULL, }
. This is inconsistent and in many cases incorrect. NULL
is commonly #defined as ((void*)0)
, thus an invalid initializer for char
. path
could be initialized this way:
char path[1024] = { 0 };
To avoid overflowing the destination buffer, use this code:
char path[1024] = { 0 };
char *p = getenv("A");
if (p != NULL) {
strncat(path, p, sizeof(path) - 1);
}
But this would truncate the environment value, which may not be appropriate depending on how you use path
.
An alternative is to use the environment value directly:
char *path = getenv("A");
if (path == NULL)
path = "";
And if you change the environment values with setenv
during the execution of your program, you might want to make a copy of the environment value with path = strdup(path);
. This might also fix the tainted string warning from Coverity, although the copy would be the same size as the original and enough memory might not be available, which should be tested. Judging from Tainted string in C , it seems Coverity is a bit extreme about tainted strings. While the warning you get indicates a real problem, getting rid of the warning may sometimes require strange workarounds.
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