Tableview scroll content when keyboard shows

Question

I have a table view with a text field and a textview. I've implemented this code like suggested by this apple sample code https://developer.apple.com/library/ios/documentation/StringsTextFonts/Conceptual/TextAndWebiPhoneOS/KeyboardManagement/KeyboardManagement.html

@IBOutlet var myTableView: UITableView func keyboardWasShown (notification: NSNotification) {     println("keyboard was shown")     var info = notification.userInfo     var keyboardSize = info.objectForKey(UIKeyboardFrameBeginUserInfoKey).CGRectValue().size      myTableView.contentInset = UIEdgeInsetsMake(0, 0, keyboardSize.height, 0)     myTableView.scrollIndicatorInsets = myTableView.contentInset }  func keyboardWillBeHidden (notification: NSNotification) {     println("keyboard will be hidden")     myTableView.contentInset = UIEdgeInsetsZero     myTableView.scrollIndicatorInsets = UIEdgeInsetsZero }   override func viewDidLoad() {      super.viewDidLoad()      NSNotificationCenter.defaultCenter().addObserver(self, selector: "keyboardWasShown:", name: UIKeyboardDidShowNotification, object: nil)     NSNotificationCenter.defaultCenter().addObserver(self, selector: "keyboardWillBeHidden:", name: UIKeyboardWillHideNotification, object: nil)  } 

When i click on the "text" of the scroll view go just above the top of the screen, but when i release the keyboard it remains scrolled up. It's just like the insets property can't be modified after the first time. What's my mistake?

Answer 1

override func viewDidLoad() {     super.viewDidLoad()      NotificationCenter.default.addObserver(self, selector: #selector(ViewController.keyboardWillShow), name: NSNotification.Name.UIKeyboardWillShow, object: nil)      NotificationCenter.default.addObserver(self, selector: #selector(ViewController.keyboardWillHide), name: NSNotification.Name.UIKeyboardWillHide, object: nil)  }  func keyboardWillShow(_ notification:Notification) {      if let keyboardSize = (notification.userInfo?[UIKeyboardFrameBeginUserInfoKey] as? NSValue)?.cgRectValue {         tableView.contentInset = UIEdgeInsetsMake(0, 0, keyboardSize.height, 0)     } } func keyboardWillHide(_ notification:Notification) {      if let keyboardSize = (notification.userInfo?[UIKeyboardFrameBeginUserInfoKey] as? NSValue)?.cgRectValue {         tableView.contentInset = UIEdgeInsetsMake(0, 0, 0, 0)     } } 

Answer 2

For Swift 4.2

In viewDidLoad() of your UIViewController:

NotificationCenter.default.addObserver(self, selector: #selector(keyboardWillShow(notification:)), name: UIResponder.keyboardWillShowNotification, object: nil) NotificationCenter.default.addObserver(self, selector: #selector(keyboardWillHide(notification:)), name: UIResponder.keyboardWillHideNotification, object: nil) 

And implementation of selectors:

@objc private func keyboardWillShow(notification: NSNotification) {     if let keyboardSize = (notification.userInfo?[UIResponder.keyboardFrameBeginUserInfoKey] as? NSValue)?.cgRectValue {         tableView.contentInset = UIEdgeInsets(top: 0, left: 0, bottom: keyboardSize.height, right: 0)     } }  @objc private func keyboardWillHide(notification: NSNotification) {     tableView.contentInset = .zero }