I have some data and want to be able to number each row sequentially, but rows with the same type consecutively, number the same number, and when it's a different type continue numbering. There will only be types 5 and 6, ID is actually more complex than abc123. I've tried rank but I seem to get two different row counts - in the example instead of 1 2 2 3 4 it would be 1 1 2 2
original image
dense rank result
MS SQL 2008 R2
As far as I understand, you want to number your continous groups
declare @Temp table (id1 bigint identity(1, 1), ID nvarchar(128), Date date, Type int)
insert into @Temp
select 'abc123', '20130101', 5 union all
select 'abc124', '20130102', 6 union all
select 'abc125', '20130103', 6 union all
select 'abc126', '20130104', 5 union all
select 'abc127', '20130105', 6 union all
select 'abc128', '20130106', 6 union all
select 'abc129', '20130107', 6 union all
select 'abc130', '20130108', 6 union all
select 'abc131', '20130109', 5
;with cte1 as (
select
*,
row_number() over (order by T.Date) - row_number() over (order by T.Type, T.Date) as grp
from @Temp as T
), cte2 as (
select *, min(Date) over (partition by grp) as grp2
from cte1
)
select
T.ID, T.Date, T.Type,
dense_rank() over (order by grp2)
from cte2 as T
order by id1
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