I want to count values on a table with different where clauses and wondering if there is a better way of doing it.
In this code i count one value.
SELECT v.name, count(v.value) AS v1
FROM dbo.table as v
WHERE v.organisationID = 2
AND v.datecreated > '2018-01-01'
AND v.datecreated < '2018-05-01'
AND v.value = 1
GROUP BY v.name
I also want to count all rows with value = 2 my way of doing it is like this with a sub select.
SELECT v.name, count(v.value) AS v1, (SELECT v2.name, count(v2.value)
FROM dbo.table as v2
WHERE v2.organisationID = 2
AND v2.datecreated > '2018-01-01'
AND v2.datecreated < '2018-05-01'
AND v2.value = 2
GROUP BY v2.name) AS v2
FROM dbo.table as v
WHERE v.organisationID = 2
AND v.datecreated > '2018-01-01'
AND v.datecreated < '2018-05-01'
AND v.value = 1
GROUP BY v.name
The table contains > 100 millions rows so I really want the fastest way. I use clustered columnstore index on the table.
Is there some way of doing it whitout sub-select.
Pseudo code:
SELECT v.name, count(v.value where v.value=1) AS v1, count(v.value where v.value=2) AS v2
FROM dbo.table as v
WHERE v.organisationID = 2
AND v.datecreated > '2018-01-01'
AND v.datecreated < '2018-05-01'
GROUP BY v.name
Yes, just use a CASE
expression:
SELECT v.name,
SUM(CASE WHEN v.value = 1 THEN 1 ELSE 0 END) AS v1,
SUM(CASE WHEN v.value = 2 THEN 1 ELSE 0 END) AS v2
FROM dbo.table as v
WHERE v.organisationID = 2
AND v.datecreated > '2018-01-01'
AND v.datecreated < '2018-05-01'
AND v.value IN (1,2)
GROUP BY v.name
;
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