I need to find invalid social security numbers in a varchar field in a SQL Server 2008 database table. (Valid SSNs are being defined by being in the format ###-##-#### - doesn't matter what the numbers are, as long as they are in that "3-digit dash 2-digit dash 4-digit" pattern.
I do have a working regex:
SELECT *
FROM mytable
WHERE ssn NOT LIKE '[0-9][0-9][0-9]-[0-9][0-9]-[0-9][0-9][0-9][0-9]'
That does find the invalid SSNs in the column, but I know (okay - I'm pretty sure) that there is a way to shorten that to indicate that the previous pattern can have x iterations.
I thought this would work:
'[0-9]{3}-[0-9]{2}-[0-9]{4}'
But it doesn't.
Is there a shorter regex than the one above in the select, or not? Or perhaps there is, but T-SQL/SQL Server 2008 doesn't support it!?
If you plan to get a shorter variant of your LIKE expression, then the answer is no.
In T-SQL, you can only use the following wildcards in the pattern:
%
- Any string of zero or more characters.WHERE title LIKE '%computer%'finds all book titles with the wordcomputeranywhere in the book title._ (underscore)
Any single character.WHERE au_fname LIKE '_ean'finds all four-letter first names that end withean(Dean, Sean, and so on).
[ ]
Any single character within the specified range ([a-f]) or set ([abcdef]).WHERE au_lname LIKE '[C-P]arsen'finds author last names ending witharsenand starting with any single character betweenCandP, for exampleCarsen,Larsen,Karsen, and so on. In range searches, the characters included in the range may vary depending on the sorting rules of the collation.
[^]
Any single character not within the specified range ([^a-f]) or set ([^abcdef]).
So, your LIKE statement is already the shortest possible expression. No limiting quantifiers can be used (those like {min,max}), not shorthand classes like \d.
If you were using MySQL, you could use a richer set of regex utilities, but it is not the case.
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