I'm using an alias to refer to a computed column. Here is a snippet from the actual code I'm trying to make work, to compute similarity and return matches where the similarity score is 3 or higher.
select [FirstName], difference([FirstName], 'mitch') as similarity from [Dev].[dbo].[Name] where similarity > 2 order by similarity desc
Exception Message:
Invalid column name 'similarity'.
As similarity is not a real column, how would I make this work?
Column aliases and computations are performed in the projection (SELECT
) phase of the query, which occurs after the selection (WHERE
and JOIN
) phase. Because of this, they can't be referenced in the WHERE
clause or in a JOIN
condition because they do not yet exist. You can either use your query with the SELECT
clause as a subquery or you can duplicate the computation in the WHERE
clause:
select * from (select [FirstName], difference([FirstName], 'mitch') as similarity from [Dev].[dbo].[Name]) src where similarity > 2 order by similarity desc
or
select [FirstName], difference([FirstName], 'mitch') as similarity from [Dev].[dbo].[Name] where difference([FirstName], 'mitch') > 2 order by similarity desc
All answers can solve your problem but for complicated situation you just can't duplicate your query.
The correct way is by using CROSS and APPLY
select [FirstName], similarity from [Dev].[dbo].[Name] cross apply ( select similarity = difference([FirstName], 'mitch') )computed_column where similarity > 2 order by similarity desc
whit CROSS and APPLY you can use your computed column everywhere on the query
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