switch case with integer expression

Question

i am trying to use switch case instead of If Else statement, in which i have to first check length of string and as per that i have to make cases of it.

switch (mystring.length)
{
    case <=25:
    {
        //do this
        break;
    }
    case <50:
    {
        //do this
        break;
    }
    default:
        break;
}

This is some thing i want to do but unable to get how to put <25 in front of case because it is not appropriate as per switch case rules.

Answer 1

Its always better to use if/else for your particular case, With switch statement you can't put conditions in the case. It looks like you are checking for ranges and if the range is constant then you can try the following (if you want to use switch statement).

int Length = mystring.Length;
int range = (Length - 1) / 25;
switch (range)
{
    case 0:
        Console.WriteLine("Range between 0 to 25");
        break;
    case 1:
        Console.WriteLine("Range between 26 to 50");
        break;
    case 2:
        Console.WriteLine("Range between 51 to 75");
        break;

}

Answer 2

This really doesn't help the OP much, but hopefully it will help someone looking for this in the future.

If you're using C# 7 (Available in Visual Studio 2017), you can switch on a range.

Example:

switch (mystring.length)
{
    case int n when (n >= 0 && n <= 25):
    //do this
    break;

    case int n when (n >= 26 && n <= 50 ):
    //do this
    break;
}