Swift - Predicate to filter an array by a property of member array

Question

I need to filter out an array of MyClass3 Objects. An array of MyClass2 Objects is a member of MyClass3 object(Please refer to code below). MyClass2 object has an id. I have an idArray at hand. I need to filter out those MyClass3 objects in which all ids in idArray are present in its [MyClass2] member.

class MyClass2 : NSObject {
    var uid: Int = 0

    init(uid : Int) {
        self.uid = uid
    }
}

class MyClass3 : NSObject {
    var arr: [MyClass2]

    init(units: [MyClass2]) {
        arr = units
    }
}

var units1 = [MyClass2(uid: 1),MyClass2(uid: 2), MyClass2(uid: 3), MyClass2(uid: 4), MyClass2(uid: 5)]
var units2 = [MyClass2(uid: 4),MyClass2(uid: 5), MyClass2(uid: 6)]
var units3 = [MyClass2(uid: 3),MyClass2(uid: 5), MyClass2(uid: 7), MyClass2(uid: 1)]

var ids = [1,5]

var available3: [MyClass3] = [MyClass3(units: units1), MyClass3(units: units2), MyClass3(units: units3)]
var filtered3: [MyClass3] = []

let searchPredicate: NSPredicate = NSPredicate(format: " ANY arr.uid IN \(ids)") // needed predicate
print(searchPredicate.predicateFormat)
filtered3 = (available3 as NSArray).filteredArrayUsingPredicate(searchPredicate) as! [MyClass3]

The required answer is that we need MyClass3(units: units1) and MyClass3(units: units3) in the filtered Array.

This is not working out. Can someone suggest a predicate format for this purpose

Answer 1

Using string interpolation in predicate format strings is never a good idea. The correct form of your predicate would be

let searchPredicate = NSPredicate(format: "ANY arr.uid IN %@", ids)

However that checks if any of the uids is in the given list. To check if all uids are in the given list, the following predicate should work:

let searchPredicate = NSPredicate(format: "SUBQUERY(arr.uid, $x, $x IN %@).@count = %d", ids, ids.count)

The same can be achieved without predicates in "pure" Swift 3 as

filtered3 = available3.filter { $0.arr.filter { ids.contains($0.uid) }.count == ids.count }

or

filtered3 = available3.filter { Set(ids).isSubset(of: $0.arr.map { $0.uid }) }