Swift optional inout parameters and nil

Question

Is it possible to have an Optional inout parameter to a function in Swift? I am trying to do this:

func testFunc( inout optionalParam: MyClass? ) {     if optionalParam {         ...     } } 

...but when I try to call it and pass nil, it is giving me a strange compile error:

Type 'inout MyClass?' does not conform to protocol 'NilLiteralConvertible' 

I don't see why my class should have to conform to some special protocol when it's already declared as an optional.

Answer 1

It won't compile because the function expecting a reference but you passed nil. The problem have nothing to do with optional.

By declaring parameter with inout means that you will assign some value to it inside the function body. How can it assign value to nil?

You need to call it like

var a : MyClass? = nil testFunc(&a) // value of a can be changed inside the function 

---

If you know C++, this is C++ version of your code without optional

struct MyClass {};     void testFunc(MyClass &p) {} int main () { testFunc(nullptr); } 

and you have this error message

main.cpp:6:6: note: candidate function not viable: no known conversion from 'nullptr_t' to 'MyClass &' for 1st argument 

which is kind of equivalent to the on you got (but easier to understand)