Swift function with args... pass to another function with args

Question

I have a simple problem. I tried search in many blogs about this question but all site return how function in swift work, but I need this case.

My custom function is:

func getLocalizeWithParams(args:CVarArgType...)->String {
     return NSString.localizedStringWithFormat(self, args); //error: Expected expression in list of expressions
}

How I do to pass my args to other system function with args?

Thanks advance.

Answer 1

Similar as in (Objective-)C, you cannot pass a variable argument list directly to another function. You have to create a CVaListPointer (the Swift equivalent of va_list in C) and call a function which takes a CVaListPointer parameter.

So this could be what you are looking for:

extension String {
    func getLocalizeWithParams(args : CVarArgType...) -> String {
        return withVaList(args) {
            NSString(format: self, locale: NSLocale.currentLocale(), arguments: $0)
        } as String
    }
}

withVaList() creates a CVaListPointer from the given argument list and calls the closure with this pointer as argument.

Example (from the NSString documentation):

let msg = "%@:  %f\n".getLocalizeWithParams("Cost", 1234.56)
print(msg)

Output for US locale:

Cost:  1,234.560000

Output for German locale:

Cost:  1.234,560000

---

Update: As of Swift 3/4/5 one can pass the arguments to

String(format: String, locale: Locale?, arguments: [CVarArg])

directly:

extension String {
    func getLocalizeWithParams(_ args : CVarArg...) -> String {
        return String(format: self, locale: .current, arguments: args)
    }
}