I am getting a compile time error that myFunc reference is ambiguous.
func f (s: String) -> String { return "version 1: " + s }
func f(sourceString s: String) -> String { return "version 2: " + s }
var myFunc: (String)-> String = f as (sourceString : String)->String
How can I explicitly reference each version of the overloaded function, f, in the example above? If I comment out either declaration of func f
it will compile and work. But I would like to know how to reference each of the functions if both are declared. Thanks.
I don't know how to do exactly what you want, but maybe this helps:
var myFunc1: (String)-> String = { s in f(sourceString: s) }
var myFunc2: (String)-> String = { s in f(s) }
You can now call:
let s1 = myFunc1("one") // returns "version 2: one"
let s2 = myFunc2("two") // returns "version 1: two"
Interesting one this. I don’t think it’s possible without doing something along the lines of @marcos’s suggestion. The problem you is you can “cast away” the names in tuples:
let named_pair = (s: "hello", i: 1)
named_pair.s // hello
let anon_pair = named_pair as (String,Int)
// or anon_pair: (String,Int) = named_pair, if you prefer
anon_pair.s // no such member 's'
Now suppose you define two functions, identical except one has named arguments:
func f(s: String, i: Int) { println("_: \(s)") }
func f(#s: String, #i: Int) { println("s: \(s)") }
You can then call it via tuples with named vs unnamed arguments:
f(named_pair) // prints s: hello
f(anon_pair) // prints _: hello
// but if you try to call a named argument function with unnamed tuples:
func g(# s: String, # i: Int) { println("s: \(s)") }
g(anon_pair) // compiler error
let h = g
h(anon_pair) // compiler error
h(named_pair) // works
But because you can cast away these names you can do this:
// compiles and runs just fine...
(g as (String,Int)->())(anon_pair)
let k: (String,Int)->() = g
// as does this
k(anon_pair)
And this ability to do this means it’s not possible to use a type to disambiguate an function overloaded only by argument names, as far as I can tell.
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