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Swap rows with columns (transposition) of a matrix in javascript [duplicate]

For instance I have a matrix like this:

|1 2 3|    
|4 5 6|
|7 8 9|

and I need it to convert into a matrix like this:

|1 4 7|    
|2 5 8|
|3 6 9|

What is the best and optimal way to achieve this goal?

like image 718
Bakhtiyor Avatar asked Dec 20 '10 18:12

Bakhtiyor


3 Answers

DuckDucking turned up this by Ken. Surprisingly, it's even more concise and complete than Nikita's answer. It retrieves column and row lengths implicitly within the guts of map().

function transpose(a) {
    return Object.keys(a[0]).map(function(c) {
        return a.map(function(r) { return r[c]; });
    });
}

console.log(transpose([
    [1,2,3],
    [4,5,6],
    [7,8,9]
]));

[[1,4,5],[2,5,8],[7,8,9]

like image 108
hobs Avatar answered Oct 16 '22 18:10

hobs


See article: Transpose An Array In JavaScript and jQuery

function transpose(a) {

  // Calculate the width and height of the Array
  var w = a.length || 0;
  var h = a[0] instanceof Array ? a[0].length : 0;

  // In case it is a zero matrix, no transpose routine needed.
  if(h === 0 || w === 0) { return []; }

  /**
   * @var {Number} i Counter
   * @var {Number} j Counter
   * @var {Array} t Transposed data is stored in this array.
   */
  var i, j, t = [];

  // Loop through every item in the outer array (height)
  for(i=0; i<h; i++) {

    // Insert a new row (array)
    t[i] = [];

    // Loop through every item per item in outer array (width)
    for(j=0; j<w; j++) {

      // Save transposed data.
      t[i][j] = a[j][i];
    }
  }

  return t;
}

console.log(transpose([[1,2,3],[4,5,6],[7,8,9]]));
like image 34
troynt Avatar answered Oct 16 '22 19:10

troynt


Just like in any other language:

int[][] copy = new int[columns][rows];
for (int i = 0; i < rows; ++i) {
    for (int j = 0; j < columns; ++j) {
        copy[j][i] = original[i][j];
    }
}

You just have to construct the 2D array differently in JS. Like this:

function transpose(original) {
    var copy = [];
    for (var i = 0; i < original.length; ++i) {
        for (var j = 0; j < original[i].length; ++j) {
            // skip undefined values to preserve sparse array
            if (original[i][j] === undefined) continue;
            // create row if it doesn't exist yet
            if (copy[j] === undefined) copy[j] = [];
            // swap the x and y coords for the copy
            copy[j][i] = original[i][j];
        }
    }
    return copy;
}

console.log(transpose([
    [1,2,3],
    [4,5,6],
    [7,8,9]
]));
like image 7
Nikita Rybak Avatar answered Oct 16 '22 20:10

Nikita Rybak