I have an array like so:
var array = [
{
name: "a",
value: 1
},
{
name: "a",
value: 2
},
{
name: "a",
value: 3
},
{
name: "b",
value: 0
},
{
name: "b",
value: 1
}
];
And I need an array like this:
var newarray = [
{
name: "a",
value: 2
},
{
name: "b",
value: 0.5
}
]
Where the new array has each unique name as an object with the average value.
Is there an easy way to accomplish this?
One way to get distinct values from an array of JavaScript objects is to use the array's map method to get an array with the values of a property in each object. Then we can remove the duplicate values with the Set constructor. And then we can convert the set back to an array with the spread operator.
Average is the sum of array elements divided by the number of elements. Examples : Input : arr[] = {1, 2, 3, 4, 5} Output : 3 Sum of the elements is 1+2+3+4+5 = 15 and total number of elements is 5.
You'll have to loop through the array, computing the sum and counts for each object. Here's a quick implementation:
function average(arr) {
var sums = {}, counts = {}, results = [], name;
for (var i = 0; i < arr.length; i++) {
name = arr[i].name;
if (!(name in sums)) {
sums[name] = 0;
counts[name] = 0;
}
sums[name] += arr[i].value;
counts[name]++;
}
for(name in sums) {
results.push({ name: name, value: sums[name] / counts[name] });
}
return results;
}
Demonstration
Note, this kind of thing can be made much easier if you use a library like Underscore.js:
var averages = _.chain(array)
.groupBy('name')
.map(function(g, k) {
return {
name: k,
value: _.chain(g)
.pluck('value')
.reduce(function(x, y) { return x + y })
.value() / g.length
};
})
.value();
Demonstration
var array = [
{
name: "a",
value: 1
},
{
name: "a",
value: 2
},
{
name: "a",
value: 3
},
{
name: "b",
value: 0
},
{
name: "b",
value: 1
}
];
var sum = {};
for(var i = 0; i < array.length; i++) {
var ele = array[i];
if (!sum[ele.name]) {
sum[ele.name] = {};
sum[ele.name]["sum"] = 0;
sum[ele.name]["count"] = 0;
}
sum[ele.name]["sum"] += ele.value;
sum[ele.name]["count"]++;
}
var result = [];
for (var name in sum) {
result.push({name: name, value: sum[name]["sum"] / sum[name]["count"]});
}
console.log(result);
You can do it with Alasql library with one line of code:
var newArray = alasql('SELECT name, AVG([value]) AS [value] FROM ? GROUP BY name',
[array]);
Here I put "value" in square brackets, because VALUE is a keyword in SQL.
Try this example at jsFiddle
Here is a ES2015 version, using reduce
let arr = [
{ a: 1, b: 1 },
{ a: 2, b: 3 },
{ a: 6, b: 4 },
{ a: 2, b: 1 },
{ a: 8, b: 2 },
{ a: 0, b: 2 },
{ a: 4, b: 3 }
]
arr.reduce((a, b, index, self) => {
const keys = Object.keys(a)
let c = {}
keys.map((key) => {
c[key] = a[key] + b[key]
if (index + 1 === self.length) {
c[key] = c[key] / self.length
}
})
return c
})
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