I have nested dictionary like this:
data = {
"2010":{
'A':2,
'B':3,
'C':5,
'D':-18,
},
"2011":{
'A':1,
'B':2,
'C':3,
'D':1,
},
"2012":{
'A':1,
'B':2,
'C':4,
'D':2
}
}
In my case, i need to sum all values based on its similar keys in every year, from 2010 till 2012.. So the result i expected should be like this:
data = {'A':4,'B':7, 'C':12, 'D':-15}
The straight answer is NO. You can not have duplicate keys in a dictionary in Python.
The compare method cmp() is used in Python to compare values and keys of two dictionaries. If method returns 0 if both dictionaries are equal, 1 if dic1 > dict2 and -1 if dict1 < dict2.
In python, if we want a dictionary in which one key has multiple values, then we need to associate an object with each key as value. This value object should be capable of having various values inside it. We can either use a tuple or a list as a value in the dictionary to associate multiple values with a key.
You can use collections.Counter()
(works only for positive values!):
In [17]: from collections import Counter
In [18]: sum((Counter(d) for d in data.values()), Counter())
Out[18]: Counter({'C': 12, 'B': 7, 'A': 4, 'D': 3})
Note that based on python documentation Counter
is designed only for use cases with positive values:
The multiset methods are designed only for use cases with positive values. The inputs may be negative or zero, but only outputs with positive values are created. There are no type restrictions, but the value type needs to support addition, subtraction, and comparison. The
elements()
method requires integer counts. It ignores zero and negative counts.
So if you want to get a comprehensive result you can do the summation manually. The collections.defaultdict()
is a good way for getting around this problem:
In [28]: from collections import defaultdict
In [29]: d = defaultdict(int)
In [30]: for sub in data.values():
....: for i, j in sub.items():
....: d[i] += j
....:
In [31]: d
Out[31]: defaultdict(<class 'int'>, {'D': -15, 'A': 4, 'C': 12, 'B': 7})
Try this,
reduce(lambda x, y: dict((k, v + y[k]) for k, v in x.iteritems()), data.values())
Result
{'A': 4, 'B': 7, 'C': 12, 'D': -15}
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