I have a sql table
Project ID       Employee ID          Total Days
1                   100                   1
1                  100                   1
1                  100                   2
1                   100                   6
1                   200                   8
1                   200                   2
Now i need this table to look like
Project ID       Employee ID          Total Days
1                   100                   10
1                   200                   10
As iam new to sql,i am little confuse to use SUM() based on above condition.
This query below produces two columns: EmployeeID, totalDays.
SELECT  EmployeeID, SUM(totalDays) totalDays
FROM    tableName
GROUP BY EmployeeID
follow-up question: why is in your desired result the projectId is 1 and 2?
Here are two approaches
Declare @t Table(ProjectId Int, EmployeeId Int,TotalDays Int)
Insert Into @t Values(1,100,1),(1,100,1),(1,100,2),(1,100,6),(1,200,8),(1,200,2)
Approach1:
Select ProjectId,EmployeeId,TotalDays = Sum(TotalDays)
From @t 
Group By ProjectId,EmployeeId
Approach2:
;With Cte As(
Select 
    ProjectId
    ,EmployeeId
    ,TotalDays = Sum(TotalDays) Over(Partition By EmployeeId)
    ,Rn = Row_Number() Over(Partition By EmployeeId Order By EmployeeId)
From @t )
Select ProjectId,EmployeeId,TotalDays
From Cte Where Rn = 1
Result
ProjectId   EmployeeId  TotalDays
1            100        10
1            200        10
                        select min("Project ID")as 'Project ID',"Employee ID"
   , SUM("Total Days") as 'Total Days'
from table1
group by "Employee ID"
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