I want to subtract some minutes 15 min 10 min etc., And i am having date object with time now i want to subtract minutes.
Use following:
// gives new date object with time 15 minutes earlier
NSDate *newDate = [oldDate dateByAddingTimeInterval:-60*15];
Check out my answer to this question: NSDate substract one month
Here's a sample, modified for your question:
NSDate *today = [[NSDate alloc] init];
NSLog(@"%@", today);
NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSDateComponents *offsetComponents = [[NSDateComponents alloc] init];
[offsetComponents setMinute:-10]; // note that I'm setting it to -1
NSDate *endOfWorldWar3 = [gregorian dateByAddingComponents:offsetComponents toDate:today options:0];
NSLog(@"%@", endOfWorldWar3);
Hope this helps!
Since iOS 8 there is the more convenient dateByAddingUnit
:
//subtract 15 minutes
let calendar = NSCalendar.autoupdatingCurrentCalendar()
newDate = calendar.dateByAddingUnit(.CalendarUnitMinute, value: -15, toDate: originalDate, options: nil)
The current Swift answer is outdated as of Swift 2.x. Here's an updated version:
let originalDate = NSDate() // "Jun 8, 2016, 12:05 AM"
let calendar = NSCalendar.currentCalendar()
let newDate = calendar.dateByAddingUnit(.Minute, value: -15, toDate: originalDate, options: []) // "Jun 7, 2016, 11:50 PM"
The NSCalendarUnit
OptionSetType
value has changed to .Minute
and you can no longer pass in nil
for options
. Instead, use an empty array.
Update for Swift 3 using the new Date
and Calendar
classes:
let originalDate = Date() // "Jun 13, 2016, 1:23 PM"
let calendar = Calendar.current
let newDate = calendar.date(byAdding: .minute, value: -5, to: originalDate, options: []) // "Jun 13, 2016, 1:18 PM"
Update the code above for Swift 4:
let newDate = calendar.date(byAdding: .minute, value: -5, to: originalDate) // "Jun 13, 2016, 1:18 PM"
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