When taking a substring of a string in Go, no new memory is allocated. Instead, the underlying representation of the substring contains a Data pointer that is an offset of the original string's Data pointer.
This means that if I have a large string and wish to keep track of a small substring, the garbage collector will be unable to free any of the large string until I release all references to the shorter substring.
Slices have a similar problem, but you can get around it by making a copy of the subslice using copy(). I am unaware of any similar copy operation for strings. What is the idiomatic and fastest way to make a "copy" of a substring?
Garbage collection is a mechanism Go developers use to find memory space that is allocated recently but is no longer needed, hence the need to deallocate them to create a clean slate so that further allocation can be done on the same space or so that memory can be reused.
Go has all goroutines reach a garbage collection safe point with a process called stop the world. This temporarily stops the program from running and turns a write barrier on to maintain data integrity on the heap. This allows for concurrency by allowing goroutines and the collector to run simultaneously.
The Go GC, however, is not fully stop-the-world and does most of its work concurrently with the application. This is primarily to reduce application latencies.
In the common language runtime (CLR), the garbage collector (GC) serves as an automatic memory manager. The garbage collector manages the allocation and release of memory for an application. Therefore, developers working with managed code don't have to write code to perform memory management tasks.
For example,
package main
import (
"fmt"
"unsafe"
)
type String struct {
str *byte
len int
}
func main() {
str := "abc"
substr := string([]byte(str[1:]))
fmt.Println(str, substr)
fmt.Println(*(*String)(unsafe.Pointer(&str)), *(*String)(unsafe.Pointer(&substr)))
}
Output:
abc bc
{0x4c0640 3} {0xc21000c940 2}
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