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I have a DataFrame with columns [A, B, C, D, E, F, G, H].
An index has been made with columns [D, G, H]:
>>> print(dgh_columns)
Index(['D', 'G', 'H'], dtype='object')
How can I retrieve the original DataFrame without the columns D, G, H ?
Is there an index subset operation?
Ideally, this would be:
df[df.index - dgh_columns]
But this doesn't seem to work
800
Use DataFrame. loc[] and DataFrame. iloc[] to select a single column or multiple columns from pandas DataFrame by column names/label or index position respectively. where loc[] is used with column labels/names and iloc[] is used with column index/position.
The most straightforward way to drop a Pandas dataframe index is to use the Pandas . reset_index() method. By default, the method will only reset the index, forcing values from 0 - len(df)-1 as the index. The method will also simply insert the dataframe index into a column in the dataframe.
In order to set index to column in pandas DataFrame use reset_index() method. By using this you can also set single, multiple indexes to a column. If you are not aware by default, pandas adds an index to each row of the pandas DataFrame.
I think you can use Index.difference:
df[df.columns.difference(dgh_columns)]
Sample:
df = pd.DataFrame({'A':[1,2,3],
'B':[4,5,6],
'C':[7,8,9],
'D':[1,3,5],
'E':[7,8,9],
'F':[1,3,5],
'G':[5,3,6],
'H':[7,4,3]})
print (df)
A B C D E F G H
0 1 4 7 1 7 1 5 7
1 2 5 8 3 8 3 3 4
2 3 6 9 5 9 5 6 3
dgh_columns = pd.Index(['D', 'G', 'H'])
print (df[df.columns.difference(dgh_columns)])
A B C E F
0 1 4 7 7 1
1 2 5 8 8 3
2 3 6 9 9 5
Numpy solution with numpy.setxor1d or numpy.setdiff1d:
dgh_columns = pd.Index(['D', 'G', 'H'])
print (df[np.setxor1d(df.columns, dgh_columns)])
A B C E F
0 1 4 7 7 1
1 2 5 8 8 3
2 3 6 9 9 5
dgh_columns = pd.Index(['D', 'G', 'H'])
print (df[np.setdiff1d(df.columns, dgh_columns)])
A B C E F
0 1 4 7 7 1
1 2 5 8 8 3
2 3 6 9 9 5
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