Submitting a jQuery ajax form with two submit buttons

Question

I have a form that looks like this:

<form action="/vote/" method="post" class="vote_form">     <input type="hidden" name="question_id" value="10" />     <input type="image" src="vote_down.png" class="vote_down" name="submit" value="down" />     <input type="image" src="vote_up.png" class="vote_up" name="submit" value="up" /> </form> 

When I bind to the form's submit ($("vote_form").submit()), I don't seem to have access to which image the user clicked on. So I'm trying to bind to clicking on the image itself ($(".vote_down, .vote_up").click()), which always submits the form, regardless of whether I try

• return false;
• event.stopPropogation(); or
• event.preventDefault();

because all of those are form events.

1. Should I attach my $.post() to the form.submit() event, and if so, how do I tell which input the user clicked on, or

2. Should I attach my $.post() to the image click, and if so, how do I prevent the form from submitting also.

Here is what my jQuery code looks like now:

$(".vote_up, .vote_down").click(function (event) {     $form = $(this).parent("form");     $.post($form.attr("action"), $form.find("input").serialize() + {         'submit': $(this).attr("value")     }, function (data) {         // do something with data     });     return false; // <--- This doesn't prevent form from submitting; what does!? }); 

Answer 1

Based on Emmett's answer, my ideal fix for this was just to kill the form's submit with Javascript itself, like this:

$(".vote_form").submit(function() { return false; }); 

And that totally worked.

For completeness, some of my JS code in the original post need a little love. For example, the way I was adding to the serialize function didn't seem to work. This did:

    $form.serialize() + "&submit="+ $(this).attr("value") 

Here's my entire jQuery code:

$(".vote_form").submit(function() { return false; }); $(".vote_up, .vote_down").click(function(event) {     $form = $(this).parent("form");     $.post($form.attr("action"), $form.serialize() + "&submit="+ $(this).attr("value"), function(data) {         // do something with response (data)     }); });