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So I have to implement a form in modal, as you can see, the button in the modal are not the buttons in the form. I created the form as a child component of the modal. How can I submit the form using the button in the parent component. I am using React Semantic-UI react as my UI framework.
I think if I can hide the button in the form and trigger it using JavaScript. I think this might be achieved via getElementById, but is there a react way of doing it?
My current Modal looks like this:
<Modal open={this.props.open} onClose={this.props.onClose} size="small" dimmer={"blurring"}>
<Modal.Header> Edit Activity {this.props.name} </Modal.Header>
<Modal.Content>
<ActivityInfoForm/>
</Modal.Content>
<Modal.Actions>
<Button negative onClick={this.props.onClose}>
Cancel
</Button>
<Button positive
content='Submit'
onClick={this.makeActivityInfoUpdateHandler(this.props.activityId)} />
</Modal.Actions>
</Modal>
My form code looks like this:
<Form>
<Form.Group widths='equal'>
<Form.Input label='Activity Name' placeholder='eg. CIS 422' />
<Form.Input label='Activity End Date' placeholder='Pick a Date' />
</Form.Group>
<Form.Group widths='equal'>
<Form.Input label='Total Capacity' placeholder='eg. 30' />
<Form.Input label='Team Capacity' placeholder='eg. 3' />
</Form.Group>
</Form>
971
In the parent you should create a ref value in the constructor. In the render method when you create the child you have to define the ref value. And the button has a onclick method. In the click method you call the function you wrote in the child component.
Just create a ref in the parent component, send it to the child component and assign that ref to an invisible submit button.
To submit a form using the Enter key in React: Add a button element with type set to submit . Add an onSubmit prop that points to a submit handler function. Every time the user presses Enter, the handle submit function will be invoked.
You can pass the onSubmit click handler as a props as follows: import React, { Component } from "react"; import ReactDOM from "react-dom"; class CustomForm extends Component { render() { return ( <form onSubmit={this. props.
The simplest solution would be to use HTML form Attribute
Add "id" attribute to your form: id='my-form'
<Form id='my-form'>
<Form.Group widths='equal'>
<Form.Input label='Activity Name' placeholder='eg. CIS 422' />
<Form.Input label='Activity End Date' placeholder='Pick a Date' />
</Form.Group>
<Form.Group widths='equal'>
<Form.Input label='Total Capacity' placeholder='eg. 30' />
<Form.Input label='Team Capacity' placeholder='eg. 3' />
</Form.Group>
</Form>
Add the appropriate "form" attribute to the needed button outside of the form: form='my-form'
<Button positive form='my-form' content='Submit' value='Submit' />
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