Struggling with slice syntax to join list element of a part of a list

Question

Suppose I have a simple Python list like this:

>>> l=['0', '1', '2', '3', '4', '5', '6', '7', '8', '9']

Now suppose I want to combine l[2:6] to a single element like this:

>>> l
['0', '1', '2345', '6', '7', '8', '9']

I am able to do it in steps into a new list, like this:

>>> l2=l[0:2]
>>> l2.append(''.join(l[2:6]))
>>> l2.extend(l[6:])
>>> l2
['0', '1', '2345', '6', '7', '8', '9']

Is there a way (that I am missing) to do this more simply and in place on the original list l?

Edit

As usual, Sven Marnach had the perfect instant answer:

l[2:6] = ["".join(l[2:6])]

I had tried:

l[2:6] = "".join(l[2:6])

But without the braces, the string produced by the join was then treated as an iterable placing each character back in the list and reversing the join!

Consider:

>>> l=['abc','def','ghk','lmn','opq']
>>> l[1:3]=[''.join(l[1:3])] 
>>> l
['abc', 'defghk', 'lmn', 'opq']   #correct

>>> l=['abc','def','ghk','lmn','opq']
>>> l[1:3]=''.join(l[1:3])
>>> l
['abc', 'd', 'e', 'f', 'g', 'h', 'k', 'lmn', 'opq']   #not correct

Answer 1

Use a slice assignment:

l[2:6] = ["".join(l[2:6])]