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String.split() at a meta character +

I'm making a simple program that will deal with equations from a String input of the equation When I run it, however, I get an exception because of trying to replace the " +" with a " +" so i can split the string at the spaces. How should I go about using

the string replaceAll method to replace these special characters? Below is my code

Exception in thread "main" java.util.regex.PatternSyntaxException: Dangling meta character '+' near index 0 + ^

 public static void parse(String x){        String z = "x^2+2=2x-1";         String[] lrside =  z.split("=",4);        System.out.println("Left side: " + lrside[0] + " / Right Side: " + lrside[1]);        String rightside = lrside[0];        String leftside = lrside[1];         rightside.replaceAll("-", " -");        rightside.replaceAll("+", " +");        leftside.replaceAll("-", " -"); leftside.replaceAll("+", " +");        List<String> rightt = Arrays.asList(rightside.split(" "));        List<String> leftt = Arrays.asList(leftside.split(" "));         System.out.println(leftt);        System.out.println(rightt); 
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apache Avatar asked Apr 25 '13 14:04

apache


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1 Answers

replaceAll accepts a regular expression as its first argument.

+ is a special character which denotes a quantifier meaning one or more occurrences. Therefore it should be escaped to specify the literal character +:

rightside = rightside.replaceAll("\\+", " +"); 

(Strings are immutable so it is necessary to assign the variable to the result of replaceAll);

An alternative to this is to use a character class which removes the metacharacter status:

rightside = rightside.replaceAll("[+]", " +"); 

The simplest solution though would be to use the replace method which uses non-regex String literals:

rightside = rightside.replace("+", " +");  
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Reimeus Avatar answered Oct 08 '22 22:10

Reimeus