Actually, the best solution is using JSON:
Documentation
JSON.parse(text[, reviver]);
1)
var myobj = JSON.parse('{ "hello":"world" }');
alert(myobj.hello); // 'world'
2)
var myobj = JSON.parse(JSON.stringify({
hello: "world"
});
alert(myobj.hello); // 'world'
3) Passing a function to JSON
var obj = {
hello: "World",
sayHello: (function() {
console.log("I say Hello!");
}).toString()
};
var myobj = JSON.parse(JSON.stringify(obj));
myobj.sayHello = new Function("return ("+myobj.sayHello+")")();
myobj.sayHello();
Your string looks like a JSON string without the curly braces.
This should work then:
obj = eval('({' + str + '})');
If I'm understanding correctly:
var properties = string.split(', ');
var obj = {};
properties.forEach(function(property) {
var tup = property.split(':');
obj[tup[0]] = tup[1];
});
I'm assuming that the property name is to the left of the colon and the string value that it takes on is to the right.
Note that Array.forEach
is JavaScript 1.6 -- you may want to use a toolkit for maximum compatibility.
This simple way...
var string = "{firstName:'name1', lastName:'last1'}";
eval('var obj='+string);
alert(obj.firstName);
output
name1
Since JSON.parse() method requires the Object keys to be enclosed within quotes for it to work correctly, we would first have to convert the string into a JSON formatted string before calling JSON.parse() method.
var obj = '{ firstName:"John", lastName:"Doe" }';
var jsonStr = obj.replace(/(\w+:)|(\w+ :)/g, function(matchedStr) {
return '"' + matchedStr.substring(0, matchedStr.length - 1) + '":';
});
obj = JSON.parse(jsonStr); //converts to a regular object
console.log(obj.firstName); // expected output: John
console.log(obj.lastName); // expected output: Doe
This would work even if the string has a complex object (like the following) and it would still convert correctly. Just make sure that the string itself is enclosed within single quotes.
var strObj = '{ name:"John Doe", age:33, favorites:{ sports:["hoops", "baseball"], movies:["star wars", "taxi driver"] }}';
var jsonStr = strObj.replace(/(\w+:)|(\w+ :)/g, function(s) {
return '"' + s.substring(0, s.length-1) + '":';
});
var obj = JSON.parse(jsonStr);
console.log(obj.favorites.movies[0]); // expected output: star wars
If you have a string like foo: 1, bar: 2
you can convert it to a valid obj with:
str
.split(',')
.map(x => x.split(':').map(y => y.trim()))
.reduce((a, x) => {
a[x[0]] = x[1];
return a;
}, {});
Thanks to niggler in #javascript for that.
Update with explanations:
const obj = 'foo: 1, bar: 2'
.split(',') // split into ['foo: 1', 'bar: 2']
.map(keyVal => { // go over each keyVal value in that array
return keyVal
.split(':') // split into ['foo', '1'] and on the next loop ['bar', '2']
.map(_ => _.trim()) // loop over each value in each array and make sure it doesn't have trailing whitespace, the _ is irrelavent because i'm too lazy to think of a good var name for this
})
.reduce((accumulator, currentValue) => { // reduce() takes a func and a beginning object, we're making a fresh object
accumulator[currentValue[0]] = currentValue[1]
// accumulator starts at the beginning obj, in our case {}, and "accumulates" values to it
// since reduce() works like map() in the sense it iterates over an array, and it can be chained upon things like map(),
// first time through it would say "okay accumulator, accumulate currentValue[0] (which is 'foo') = currentValue[1] (which is '1')
// so first time reduce runs, it starts with empty object {} and assigns {foo: '1'} to it
// second time through, it "accumulates" {bar: '2'} to it. so now we have {foo: '1', bar: '2'}
return accumulator
}, {}) // when there are no more things in the array to iterate over, it returns the accumulated stuff
console.log(obj)
Confusing MDN docs:
Demo: http://jsbin.com/hiduhijevu/edit?js,console
Function:
const str2obj = str => {
return str
.split(',')
.map(keyVal => {
return keyVal
.split(':')
.map(_ => _.trim())
})
.reduce((accumulator, currentValue) => {
accumulator[currentValue[0]] = currentValue[1]
return accumulator
}, {})
}
console.log(str2obj('foo: 1, bar: 2')) // see? works!
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