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I would like to convert the string "23/02/2018" to a date format as 23-fev-2018.
Most importanly is that, the month must be in portuguese language, refering to fevereiro.
My issue is that usually the datetime.date prints like (YYYY,MM,DD):
import datetime
datestr = "23/02/2018"
dateobj = datetime.datetime.strptime(datestr, "%d/%m/%Y")
print dateobj #year, month, day
How may I print from a string as 23/10/2017 to date format as 23-out-2017, refering to the month "outubro" in portuguese?
834
Use datetime. strftime(format) to convert a datetime object into a string as per the corresponding format . The format codes are standard directives for mentioning in which format you want to represent datetime. For example, the %d-%m-%Y %H:%M:%S codes convert date to dd-mm-yyyy hh:mm:ss format.
We use the strptime() method to convert a date string to a date object.
strptime is short for "parse time" where strftime is for "formatting time". That is, strptime is the opposite of strftime though they use, conveniently, the same formatting specification.
Method #1 : Using strptime() In this, the function, strptime usually used for conversion of string date to datetime object, is used as when it doesn't match the format or date, raises the ValueError, and hence can be used to compute for validity.
Use the locale module.
import locale
import datetime
locale.setlocale(locale.LC_ALL, 'pt_pt.UTF-8')
datetime.datetime.strptime('23/10/2017', '%d/%m/%Y').strftime('%d/%B/%Y')
# '23/Outubro/2017'
datetime.datetime.strptime('23/10/2017', '%d/%m/%Y').strftime('%d/%b/%Y')
# '23/Out/2017'
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