Why it is possible to do
const string exclam = "!";
const string str = exclam + "Hello" + " world";
And not possible to do this:
const string exclam = "!";
const string str = "Hello" + " world" + exclam;
I know (although can't understand why) that it is not allowed to do:
const string str = "Hello" + " world" + "!";
as it will be interpreted like const char[6] + const char[6] + const char[1]
, so from other side, why this is not allowed also, or why it uses char[]
and not string
.
In formal language theory and computer programming, string concatenation is the operation of joining character strings end-to-end. For example, the concatenation of "snow" and "ball" is "snowball".
The concatenation of strings is a process of combining two strings to form a single string. If there are two strings, then the second string is added at the end of the first string.
Use CONCATENATE, one of the text functions, to join two or more text strings into one string. Important: In Excel 2016, Excel Mobile, and Excel for the web, this function has been replaced with the CONCAT function.
In Java, String concatenation forms a new String that is the combination of multiple strings. There are two ways to concatenate strings in Java: By + (String concatenation) operator. By concat() method.
The +
operator is left-associative (evaluated left-to-right), so the leftmost +
is evaluated first.
exclam
is a std::string
object that overloads operator+
so that both of the following perform concatenation:
exclam + "Hello"
"Hello" + exclam
Both of these return a std::string
object containing the concatenated string.
However, if the first two thing being "added" are string literals, as in:
"Hello" + "World"
there is no class type object involved (there is no std::string
here). The string literals are converted to pointers and there is no built-in operator+
for pointers.
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