What is the benefit and trade-off of using a string builder over pure string concatenation?
new StringBuilder(32).append(str1) .append(" test: ") .append(val) .append(" is changed") .toString();
vs say
str1 + " test: " + val + " is changed".
str1
is a random 10 character string. str2
is a random 8 character string.
It is always better to use StringBuilder. append to concatenate two string values.
Note that regular string concatenations are faster than using the StringBuilder but only when you're using a few of them at a time. If you are using two or three string concatenations, use a string.
StringBuilder is faster because StringBuilder is a mutable class while Sting is an immutable class. In StringBuilder we can use the + operator mean you can append by the same object so it is much faster. In the String class if you append then it should be created a new object.
StringBuilder and String are completely different objects.
In your particular example, none because the compiler internally uses StringBuilder
s to do String concatenation. If the concatenation occurred in a loop, however, the compiler could create several StringBuilder
and String
objects. For example:
String s= "" ; for(int i= 0 ; i < 10 ; i++ ) s+= "a" ;
Each time line 3 above is executed, a new StringBuilder
object is created, the contents of s
appended, "a" appended, and then the StringBuilder
is converted into a String to be assigned back to s
. A total of 10 StringBuilder
s and 10 String
s.
Conversely, in
StringBuilder sb= new StringBuilder() ; for(int i= 0 ; i < 10 ; i++ ) sb.append( "a" ); String s= sb.toString() ;
Only 1 StringBuilder
and 1 String
are created.
The main reason for this is that the compiler could not be smart enough to understand that the first loop is equivalent to the second and generate more efficient (byte) code. In more complex cases, it's impossible even for the smartest compiler to know. If you absolutely need this optimization, you have to introduce it manually by using StringBuilder
s explicitly.
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