Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

Strange OutOfMemory issue while loading an image to a Bitmap object

People also ask

How to fix out of memory error in android?

If you haven't seen any OOM in your Android application, then you are going to have one in future. The OutOfMemoryError comes in Android due to memory leaks. So, in order to remove the OutOfMemoryError, you need to remove memory leaks from your Android application.

How do you handle bitmap in Android as it takes too much memory?

Choose the most appropriate decode method based on your image data source. These methods attempt to allocate memory for the constructed bitmap and therefore can easily result in an OutOfMemory exception. Each type of decode method has additional signatures that let you specify decoding options via the BitmapFactory.

What is inJustDecodeBounds?

inJustDecodeBounds. If set to true, the decoder will return null (no bitmap), but the out... public boolean. inMutable. If set, decode methods will always return a mutable Bitmap instead of an immutable one.

How do you clear a bitmap?

You can use eraseColor on bitmap to set its color to Transparent. It will useable again without recreating it. cleanest solution.


To fix the OutOfMemory error, you should do something like this:

BitmapFactory.Options options = new BitmapFactory.Options();
options.inSampleSize = 8;
Bitmap preview_bitmap = BitmapFactory.decodeStream(is, null, options);

This inSampleSize option reduces memory consumption.

Here's a complete method. First it reads image size without decoding the content itself. Then it finds the best inSampleSize value, it should be a power of 2, and finally the image is decoded.

// Decodes image and scales it to reduce memory consumption
private Bitmap decodeFile(File f) {
    try {
        // Decode image size
        BitmapFactory.Options o = new BitmapFactory.Options();
        o.inJustDecodeBounds = true;
        BitmapFactory.decodeStream(new FileInputStream(f), null, o);

        // The new size we want to scale to
        final int REQUIRED_SIZE=70;

        // Find the correct scale value. It should be the power of 2.
        int scale = 1;
        while(o.outWidth / scale / 2 >= REQUIRED_SIZE && 
              o.outHeight / scale / 2 >= REQUIRED_SIZE) {
            scale *= 2;
        }

        // Decode with inSampleSize
        BitmapFactory.Options o2 = new BitmapFactory.Options();
        o2.inSampleSize = scale;
        return BitmapFactory.decodeStream(new FileInputStream(f), null, o2);
    } catch (FileNotFoundException e) {}
    return null;
}

The Android Training class, "Displaying Bitmaps Efficiently", offers some great information for understanding and dealing with the exception `java.lang.OutOfMemoryError: bitmap size exceeds VM budget when loading Bitmaps.


Read Bitmap Dimensions and Type

The BitmapFactory class provides several decoding methods (decodeByteArray(), decodeFile(), decodeResource(), etc.) for creating a Bitmap from various sources. Choose the most appropriate decode method based on your image data source. These methods attempt to allocate memory for the constructed bitmap and therefore can easily result in an OutOfMemory exception. Each type of decode method has additional signatures that let you specify decoding options via the BitmapFactory.Options class. Setting the inJustDecodeBounds property to true while decoding avoids memory allocation, returning null for the bitmap object but setting outWidth, outHeight and outMimeType. This technique allows you to read the dimensions and type of the image data prior to the construction (and memory allocation) of the bitmap.

BitmapFactory.Options options = new BitmapFactory.Options();
options.inJustDecodeBounds = true;
BitmapFactory.decodeResource(getResources(), R.id.myimage, options);
int imageHeight = options.outHeight;
int imageWidth = options.outWidth;
String imageType = options.outMimeType;

To avoid java.lang.OutOfMemory exceptions, check the dimensions of a bitmap before decoding it unless you absolutely trust the source to provide you with predictably sized image data that comfortably fits within the available memory.


Load a scaled-down version into Memory

Now that the image dimensions are known, they can be used to decide if the full image should be loaded into memory or if a subsampled version should be loaded instead. Here are some factors to consider:

  • Estimated memory usage of loading the full image in memory.
  • The amount of memory you are willing to commit to loading this image given any other memory requirements of your application.
  • Dimensions of the target ImageView or UI component that the image is to be loaded into.
  • Screen size and density of the current device.

For example, it’s not worth loading a 1024x768 pixel image into memory if it will eventually be displayed in a 128x96 pixel thumbnail in an ImageView.

To tell the decoder to subsample the image, loading a smaller version into memory, set inSampleSize to true in your BitmapFactory.Options object. For example, an image with resolution 2048x1536 that is decoded with an inSampleSize of 4 produces a bitmap of approximately 512x384. Loading this into memory uses 0.75MB rather than 12MB for the full image (assuming a bitmap configuration of ARGB_8888). Here’s a method to calculate a sample size value that is a power of two based on a target width and height:

public static int calculateInSampleSize(
        BitmapFactory.Options options, int reqWidth, int reqHeight) {
    // Raw height and width of image
    final int height = options.outHeight;
    final int width = options.outWidth;
    int inSampleSize = 1;

    if (height > reqHeight || width > reqWidth) {

        final int halfHeight = height / 2;
        final int halfWidth = width / 2;

        // Calculate the largest inSampleSize value that is a power of 2 and keeps both
        // height and width larger than the requested height and width.
        while ((halfHeight / inSampleSize) > reqHeight
                && (halfWidth / inSampleSize) > reqWidth) {
            inSampleSize *= 2;
        }
    }

    return inSampleSize;
}

Note: A power of two value is calculated because the decoder uses a final value by rounding down to the nearest power of two, as per the inSampleSize documentation.

To use this method, first decode with inJustDecodeBounds set to true, pass the options through and then decode again using the new inSampleSizevalue andinJustDecodeBoundsset tofalse`:

public static Bitmap decodeSampledBitmapFromResource(Resources res, int resId,
    int reqWidth, int reqHeight) {

    // First decode with inJustDecodeBounds=true to check dimensions
    final BitmapFactory.Options options = new BitmapFactory.Options();
    options.inJustDecodeBounds = true;
    BitmapFactory.decodeResource(res, resId, options);

    // Calculate inSampleSize
    options.inSampleSize = calculateInSampleSize(options, reqWidth, reqHeight);

    // Decode bitmap with inSampleSize set
    options.inJustDecodeBounds = false;
    return BitmapFactory.decodeResource(res, resId, options);
}

This method makes it easy to load a bitmap of arbitrarily large size into an ImageView that displays a 100x100 pixel thumbnail, as shown in the following example code:

mImageView.setImageBitmap(
    decodeSampledBitmapFromResource(getResources(), R.id.myimage, 100, 100));

You can follow a similar process to decode bitmaps from other sources, by substituting the appropriate BitmapFactory.decode* method as needed.


I've made a small improvement to Fedor's code. It basically does the same, but without the (in my opinion) ugly while loop and it always results in a power of two. Kudos to Fedor for making the original solution, I was stuck until I found his, and then I was able to make this one :)

 private Bitmap decodeFile(File f){
    Bitmap b = null;

        //Decode image size
    BitmapFactory.Options o = new BitmapFactory.Options();
    o.inJustDecodeBounds = true;

    FileInputStream fis = new FileInputStream(f);
    BitmapFactory.decodeStream(fis, null, o);
    fis.close();

    int scale = 1;
    if (o.outHeight > IMAGE_MAX_SIZE || o.outWidth > IMAGE_MAX_SIZE) {
        scale = (int)Math.pow(2, (int) Math.ceil(Math.log(IMAGE_MAX_SIZE / 
           (double) Math.max(o.outHeight, o.outWidth)) / Math.log(0.5)));
    }

    //Decode with inSampleSize
    BitmapFactory.Options o2 = new BitmapFactory.Options();
    o2.inSampleSize = scale;
    fis = new FileInputStream(f);
    b = BitmapFactory.decodeStream(fis, null, o2);
    fis.close();

    return b;
}

I come from iOS experience and I was frustrated to discover an issue with something so basic as loading and showing an image. After all, everyone that is having this issue is trying to display reasonably sized images. Anyway, here are the two changes that fixed my problem (and made my app very responsive).

1) Every time you do BitmapFactory.decodeXYZ(), make sure to pass in a BitmapFactory.Options with inPurgeable set to true (and preferably with inInputShareable also set to true).

2) NEVER use Bitmap.createBitmap(width, height, Config.ARGB_8888). I mean NEVER! I've never had that thing not raise memory error after few passes. No amount of recycle(), System.gc(), whatever helped. It always raised exception. The one other way that actually works is to have a dummy image in your drawables (or another Bitmap that you decoded using step 1 above), rescale that to whatever you want, then manipulate the resulting Bitmap (such as passing it on to a Canvas for more fun). So, what you should use instead is: Bitmap.createScaledBitmap(srcBitmap, width, height, false). If for whatever reason you MUST use the brute force create method, then at least pass Config.ARGB_4444.

This is almost guaranteed to save you hours if not days. All that talk about scaling the image, etc. does not really work (unless you consider getting wrong size or degraded image a solution).


It's a known bug, it's not because of large files. Since Android Caches the Drawables, it's going out of memory after using few images. But I've found an alternate way for it, by skipping the android default cache system.

Solution: Move the images to "assets" folder and use the following function to get BitmapDrawable:

public static Drawable getAssetImage(Context context, String filename) throws IOException {
    AssetManager assets = context.getResources().getAssets();
    InputStream buffer = new BufferedInputStream((assets.open("drawable/" + filename + ".png")));
    Bitmap bitmap = BitmapFactory.decodeStream(buffer);
    return new BitmapDrawable(context.getResources(), bitmap);
}