So I have the following code:
/// <summary>
/// The 'Prototype' abstract class
/// </summary>
abstract class ColorPrototype
{
public abstract ColorPrototype Clone();
}
/// <summary>
/// The 'ConcretePrototype' class
/// </summary>
class Color : ColorPrototype
{
private int _red;
private int _green;
private int _blue;
// Constructor
public Color(int red, int green, int blue)
{
this._red = red;
this._green = green;
this._blue = blue;
}
// Create a shallow copy
public override ColorPrototype Clone()
{
Console.WriteLine(
"Cloning color RGB: {0,3},{1,3},{2,3}",
_red, _green, _blue);
return this.MemberwiseClone() as ColorPrototype;
}
}
/// <summary>
/// Prototype manager
/// </summary>
class ColorManager
{
private Dictionary<string, ColorPrototype> _colors =
new Dictionary<string, ColorPrototype>();
// Indexer
public ColorPrototype this[string key]
{
get { return _colors[key]; }
set { _colors.Add(key, value); }
}
}
And in the main method I have:
ColorManager colormanager = new ColorManager();
// Initialize with standard colors
colormanager["red"] = new Color(255, 0, 0);
// User clones selected colors
ColorPrototype p1 = colormanager["red"].Clone();
bool isColor = p1 is Prototype.Color;
Color color1 = p1 as Color;
My question is why the variable p1 has type Color
(isColor
is true) if in the clone method I cast the result to ColorPrototype
(return this.MemberwiseClone() as ColorPrototype;
) ?
Reference: http://www.dofactory.com/net/prototype-design-pattern
this.MemberwiseClone()
returns you Color
object. So p1
is actually a Color
.
It does not matter if you upcast it to ColorPrototype
. Its runtime type is still Color
. This is the same as:
string s = "foo";
object o = s as object;
// runtime o type is still string
if in the clone method I cast the result to ColorPrototype
Because even though you cast p1
to a ColorPrototype
, the runtime type of p1
is still of type Color
. Casting a reference type allows you to view a type T
as type U
, but it doesn't alter the underlying runtime type.
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