Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

SQLALchemy-Utils: Use '~' operator with LTree

I am trying to query Postgres materialized path view(ltree) using Flask,SQLAlchemy-Utils and Flask-SQLAlchemy. SQLAlchemy-Util Docs shows the usage of '==', '!=' operators using LTree. How can i use '~' operator?

I saw the code in sqlalchemy_utils/ltree.py:

class comparator_factory(types.Concatenable.Comparator):
    def ancestor_of(self, other):
        if isinstance(other, list):
            return self.op('@>')(expression.cast(other, ARRAY(LtreeType)))
        else:
            return self.op('@>')(other)

    def descendant_of(self, other):
        if isinstance(other, list):
            return self.op('<@')(expression.cast(other, ARRAY(LtreeType)))
        else:
            return self.op('<@')(other)

    def lquery(self, other):
        if isinstance(other, list):
            return self.op('?')(expression.cast(other, ARRAY(LQUERY)))
        else:
            return self.op('~')(other)

    def ltxtquery(self, other):
        return self.op('@')(other)

This is subclass of LtreeType.

For a simple ==, i am using :

Model.query.filter(Model.path == LTree('1.2')).all()

But using this expression throws validation error:

Model.query.filter(Model.path == LTree('~1.2')).all()

How can i format above expression in a valid SQLALchemy query?

like image 703
Sohaib Farooqi Avatar asked Oct 19 '16 17:10

Sohaib Farooqi


People also ask

Should I create a gist or B-tree index in SQLAlchemy?

If you just pass index=True when defining your SQLAlchemy Column () , you’ll get a B-tree index, which can speed up simple comparison operations. However, in order to take full advantage of Ltree capabilities, it’s better to create a GiST index.

What is ltree in PostgreSQL?

Postgres actually offers a custom data type called LTree specifically designed to record materialized paths for representing trees.

What is adjacency list pattern in SQL alchemy?

Perhaps the most straightforward is the adjacency list pattern, where each row records one edge, represented by references to the parent and child nodes.The SQLAlchemy documentation contains an example of how to implement this pattern using its object-relational model (ORM).


1 Answers

I was able to solve this issue with this piece of code.

Courtesy Github-Issues: SQLAlchemy-Util Issues (253)

 from sqlalchemy.sql import expression
 from sqlalchemy_utils.types.ltree import LQUERY

 custom_lquery = '*.some.pattern'
 Model.query.filter(Model.path.lquery(expression.cast(custom_lquery, LQUERY))).all()
like image 52
Sohaib Farooqi Avatar answered Oct 09 '22 06:10

Sohaib Farooqi