SQL syntax: select only if more than X results

Question

I have a table with measurements called measures. The table has one column for the location and a second colum for a corresponding value (example is simplified).

The table looks like (note 2 entries for loc1):

location | value
-----------------
loc1     | value1
loc1     | value2
loc2     | value3
loc3     | value4
loc4     | value5

i now want to formulate a SQL query (actually i use sqlite) which only returns the first two rows of the table (i.e. loc+value1 and loc1+value2), because this location has more than one entry in this table.

the pseudotext formulation would be: show me the rows of the locations, which are present more than once in the whole table
pseudcode:

SELECT * from measures WHERE COUNT(location over the whole table) > 1

the solution may be really simple, but somehow i seem not to crack the nut.

what i have so far is a SELECT statement, which returns locations which have more than one entry. as a next step i would need exactly all rows which correspond to the locations returned from this query:

SELECT location FROM measures GROUP BY location HAVING count(*) > 1

so as a next step i tried to do a JOIN with the same table and incorporate above query, but the results are incorrect. i tried it like this, but this is wrong:

select t1.location, t1.value
from 
     measures as t1
     join 
     measures as t2 on t1.location = t2.location 
group by
      t2.location 
having count(*) > 1

help is appreciated!

Answer 1

You were right to use HAVING, and to think about using the self-join... just had the order of the operations slightly off...

select m1.location, m1.value
from measures m1
join (
  select location
  from measures
  group by location
  having count(*) > 1
) m2 on m2.location = m1.location

The sub-select gets all the locations that have more than one entry... and then this is joined to the table again to get the full results.

SQL Fiddle