I have a typical Persons table and an Orders table defined in such a way that I can do JOIN query as the following to return Orders for all Persons.
SELECT Persons.LastName, Persons.FirstName, Orders.OrderNo
FROM Persons
INNER JOIN Orders
ON Persons.id=Orders.Person_id
The question is, how do I write a statement that would return all Persons with NO Orders?
I'm using mysql.
Thank all in advance.
The first step is to use the GROUP BY clause to create the groups (in our example, we group by the country column). Then, in the ORDER BY clause, you use the aggregate function COUNT, which counts the number of values in the column of your choice; in our example, we count distinct IDs with COUNT(id) .
The SQL SELECT statement is used to retrieve records from one or more tables in your SQL database.
If you don't specify an ORDER BY , then there is NO ORDER defined. The results can be returned in an arbitrary order - and that might change over time, too.
You may want to use LEFT JOIN
and IS NULL
:
SELECT Persons.LastName, Persons.FirstName
FROM Persons
LEFT JOIN Orders ON Persons.id = Orders.Person_id
WHERE Orders.Person_id IS NULL;
The result of a left join always contains all records of the "left" table (Persons), even if the join-condition does not find any matching record in the "right" table (Orders). When there is no match, the columns of the "right" table will NULL
in the result set.
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