I am trying to pivot on multiple columns. I am using SQL server 2008. Here is what I have tried so far
CREATE TABLE #t ( id int, Rscd varchar(10),Accd varchar(10),position int)
INSERT INTO #t Values (10,'A','B',1)
INSERT INTO #t Values (10,'C','D',2)
Select id,[1],[2],[11],[12] FROM
(SELECT id, Rscd,Accd, position , position +10 as Aposition
From #t)
As query
PIVOT (MAX(Rscd )
FOR Position IN ([1],[2])) AS Pivot1
PIVOT (MAX(Accd )
FOR Aposition IN ([11],[12])) AS Pivot2
The below indicated is the result that I am getting
id 1 2 11 12
10 NULL C NULL D
10 A NULL B NULL
But the result that I am trying to achieve is ,
id 1 2 11 12
10 A C B D
Any help ? what is wrong in my code.
You gotta change the name of columns for next Pivot Statement. You can use aggregate of pv3 to sum and group by the column you need. The key point here is that you create new category values by appending 1 or 2 to the end. Without doing this, the pivot query won't work properly.
To have multiple columns: Click in one of the cells of your pivot table. Click your right mouse button and select Pivot table Options in the context menu, this will open a form with tabs. Click on the tab Display and tag the check box Classic Pivot table layout.
One easy way to pivot multiple columns is to just use Aggregate(Case) expressions. Save this answer. Show activity on this post. Use a GROUP BY ItemID, with aggregate function SUM(isnull(value,0)) on each of the results columns.
I would unpivot the columns into pairs first, then pivot them. Basically the unpivot process will convert the pairs of columns (rscd
, position
and accd
, aposition
) into rows, then you can apply the pivot. The code will be:
select id, [1], [2], [11], [12]
from
(
select id, col, value
from #t
cross apply
(
select rscd, position union all
select Accd, position + 10
) c (value, col)
) d
pivot
(
max(value)
for col in ([1], [2], [11], [12])
) piv;
See SQL Fiddle with Demo
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