I have an SQL table with one column (dateRec) containing dates, format: yyyy-mm-dd.
Is there a way in SQL that I can define date ranges and then group all the items by these ranges ? I would need the following groups here:
My standard query to fetch all items from that table:
CREATE PROCEDURE [dbo].[FetchRequests] AS BEGIN SET NOCOUNT ON; SELECT subject, dateRec, category FROM LogRequests WHERE logStatus = 'active' ORDER BY dateRec desc, subject FOR XML PATH('items'), ELEMENTS, TYPE, ROOT('ranks') END
Thanks for any help with this, Tim.
You need to do something like this
select t.range as [score range], count(*) as [number of occurences] from ( select case when score between 0 and 9 then ' 0-9 ' when score between 10 and 19 then '10-19' when score between 20 and 29 then '20-29' ... else '90-99' end as range from scores) t group by t.range
Check this link In SQL, how can you "group by" in ranges?
Yes, you can do that by adding a new column which contains all the bands you require and then group by that column:
SELECT subject, dateRec, category ,case when datediff(day,dateRec,Getdate())<='7' then '0 - 7 days old' when datediff(day,dateRec,Getdate()) between '8' and '14' then '8 - 14 days old' when datediff(day,dateRec,Getdate()) >60 then 'rest' end Classes into #temp1 FROM LogRequests WHERE logStatus = 'active' ORDER BY dateRec desc, subject
I have missed couple of your ranges, but hopefully you got the logic
then Group by this column:
select classes, Count(*) from #temp1 begin drop table #temp1 end
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