I am trying to do this query. This is what I have.
My table is: Table
StudyID FacultyID Year    Access1   Access2    Access3
1          1       2014       4        8          5
1          2       2014       8        4          7
1          1       2013       5        4          4
2          3       2014       4        6          5
2          5       2013       5        8         10
2          4       2014       5        5          7
3          7       2013       9        4          7
I want to group by StudyID and Year and get the minimum value of each field Access1 Access2 and Access3 and show only the last year, I mean for each group the first row. Here is the Result.
StudyID  Year    Access1   Access2    Access3
1        2014       4        4          5
2        2014       4        5          5
3        2013       9        4          7
This is my Query:
SELECT DISTINCT T.StudyID, T.Year, MIN(T.Access1), MIN(T.Access2), MIN(T.Access3)
FROM T
GROUP BY T.StudyID, T.Year
ORDER BY T.StudyID, T.Year DESC
I also tried with this one.
 ;WITH MyQuery AS (     SELECT DISTINCT T.StudyID, T.Year, MIN(T.Access1), MIN(T.Access2), MIN(T.Access3),ROW_NUMBER() OVER (PARTITION BY T.StudyID, T.Year ORDER BY T.StudyID, T.Year DESC) AS rownumber
    FROM T  GROUP BY T.StudyID, T.Year      ORDER BY T.StudyID , T.Year DESC ) SELECT * FROM MyQuery WHERE rownumber = 1
Any success, I know I am missing something...but dont know what? Thanks in advance!!!!
You can GROUP BY StudyID, Year and then in an outer query select the first row from each StudyID, Year group:
SELECT StudyID, Year, minAccess1, minAccess2, minAccess3
FROM (
   SELECT StudyID, Year, min(Access1) minAccess1, min(Access2) minAccess2,
          min(Access3) minAccess3, 
          ROW_NUMBER() OVER (PARTITION BY StudyID ORDER BY Year DESC) AS rn 
   FROM mytable
   GROUP BY StudyID, Year ) t
WHERE t.rn = 1
ROW_NUMBER is used to assign an ordering number to each StudyID group according to Year values. The row with the maximum Year value is assigned a rn = 1.
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