SQL Server Group By Order By Where

Question

I have a single table which I need to pull back the 5 most recent records based on a userID and keying off of documentID (no duplicates). Basically, I'm tracking visited pages and trying to pull back the 3 most recent by user.

Sample data:

╔══════════════════════════════════════════════╗
║UserID   DocumentID   CreatedDate             ║
╠══════════════════════════════════════════════╣
║  71         22       2013-09-09 12:19:37.930 ║
║  71         25       2013-09-09 12:20:37.930 ║
║  72          1       2012-11-09 12:19:37.930 ║
║  99         76       2012-10-10 12:19:37.930 ║
║  71         22       2013-09-09 12:19:37.930 ║
╚══════════════════════════════════════════════╝

Desired query results if UserID = 71:

╔══════════════════════════════════════════════╗
║UserID    DocumentID  CreatedDate             ║
╠══════════════════════════════════════════════╣
║  71         25       2013-09-09 12:20:37.930 ║
║  71         22       2013-09-09 12:19:37.930 ║
╚══════════════════════════════════════════════╝

Answer 1

SELECT TOP 3 UserId, DocumentId, MAX(CreatedDate)
FROM MyTable
WHERE UserId = 71
GROUP BY UserId, DocumentId
ORDER BY MAX(CreatedDate) DESC

Answer 2

You could try using a CTE and ROW_NUMBER.

Something like

;WITH Vals AS (
    SELECT UserID, 
           DocumentID, 
           ROW_NUMBER() OVER(PARTITION BY UserID, DocumnentID ORDER BY CreatedDate DESC) RowID
    FROM MyTable
)
SELECT TOP 3 *
FROM Vals
WHERE UserID = 71
AND RowID = 1