I have a query where I wish to retrieve the oldest X records. At present my query is something like the following:
SELECT Id, Title, Comments, CreatedDate
FROM MyTable
WHERE CreatedDate > @OlderThanDate
ORDER BY CreatedDate DESC
I know that normally I would remove the 'DESC' keyword to switch the order of the records, however in this instance I still want to get records ordered with the newest item first.
So I want to know if there is any means of performing this query such that I get the oldest X items sorted such that the newest item is first. I should also add that my database exists on SQL Server 2005.
The following is the syntax to get the last 10 records from the table. Here, we have used LIMIT clause. SELECT * FROM ( SELECT * FROM yourTableName ORDER BY id DESC LIMIT 10 )Var1 ORDER BY id ASC; Let us now implement the above query.
This one-liner is the simplest query in the list, to get the last 3 number of records in a table. The TOP clause in SQL Server returns the first N number of records or rows from a table. Applying the ORDER BY clause with DESC, will return rows in descending order. Hence, we get the last 3 rows.
Just press "End" key when you are in the Results tab. After that you will be at end of columns.
Why not just use a subquery?
SELECT T1.*
FROM
(SELECT TOP X Id, Title, Comments, CreatedDate
FROM MyTable
WHERE CreatedDate > @OlderThanDate
ORDER BY CreatedDate) T1
ORDER BY CreatedDate DESC
Embed the query. You take the top x when sorted in ascending order (i.e. the oldest) and then re-sort those in descending order ...
select *
from
(
SELECT top X Id, Title, Comments, CreatedDate
FROM MyTable
WHERE CreatedDate > @OlderThanDate
ORDER BY CreatedDate
) a
order by createddate desc
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