Table 1 Table 2
Number | Code Code | Description
1234 A A Something
1235 B C Something else
1246 C D Something other
1247 A
1248 B
1249 A
I would like to find the distinct Code
values and get a return like this:
1 | 2
-------
A A
B
C C
D
I can't figure out how to write a SQL query that would return me the above results. Anyone have any experience with a query like this or similar?
In Standard SQL, using relational operators and avoiding nulls:
SELECT Code AS col_1, Code AS col_2
FROM Table_1
INTERSECT
SELECT Code AS col_1, Code AS col_2
FROM Table_2
UNION
SELECT Code AS col_1, 'missing' AS col_2
FROM Table_1
EXCEPT
SELECT Code AS col_1, 'missing' AS col_2
FROM Table_2
UNION
SELECT 'missing' AS col_1, Code AS col_2
FROM Table_2
EXCEPT
SELECT 'missing' AS col_1, Code AS col_2
FROM Table_1;
Again in Standard SQL, this time using constructs that MySQL actually supports:
SELECT Code AS col_1, Code AS col_2
FROM Table_1
WHERE EXISTS (
SELECT *
FROM Table_2
WHERE Table_2.Code = Table_1.Code
)
UNION
SELECT Code AS col_1, 'missing' AS col_2
FROM Table_1
WHERE NOT EXISTS (
SELECT *
FROM Table_2
WHERE Table_2.Code = Table_1.Code
)
UNION
SELECT 'missing' AS col_1, Code AS col_2
FROM Table_2
WHERE NOT EXISTS (
SELECT *
FROM Table_1
WHERE Table_1.Code = Table_2.Code
);
In proper RDBMS:
SELECT
T1.Code, T2.Code
FROM
(SELECT DISTINCT Code FROM Table1) T1
FULL OUTER JOIN
(SELECT DISTINCT Code FROM Table2) T2
ON T1.Code = T2.Code
In MySQL... the UNION removes duplicates
SELECT
T1.Code, T2.Code
FROM
Table1 T1
LEFT OUTER JOIN
Table2 T2 ON T1.Code = T2.Code
UNION
SELECT
T1.Code, T2.Code
FROM
Table1 T1
RIGHT OUTER JOIN
Table2 T2 ON T1.Code = T2.Code
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