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SQL query not working as expected (from a beginners point of view)

Tags:

sql

mysql

I am trying to get all the rows with the specific session_id and also that do not have '3223' for the group_with column. So I have this SQL statement :

SELECT * FROM pr_cart WHERE session_id=203130570714 AND group_with != 3223

Which to me it looks fine, but for some reason it does not return anything.

In my table I have entries that should not meet the criteria. i.e.

session_id=203130570714 | group_with=3225 which should be returned. session_id=203130570714 | group_with=NULL which should be returned. session_id=203130570714 | group_with=3223 which should not be returned.

I tried:

  1. <> instead of !=
  2. NOT (group_with=3223)
  3. group_with NOT LIKE '3223'

How can I get all the rows with the specified session_id and that also have a different number than 3223 for the group_with

edit session_id is varchar and group_with is int

like image 936
hahaha Avatar asked Aug 07 '14 11:08

hahaha


Video Answer


1 Answers

NULL is a special value which you must take special care of:

SELECT * FROM pr_cart WHERE session_id="203130570714" AND
  (group_with != 3223 OR group_with IS NULL)

General recommendation

Basically all operations, which involve NULL as one operand, yield NULL as result.

SELECT NULL + 5; # NULL
SELECT NULL * 5; # NULL
SELECT NULL NOT IN (234); # NULL
SELECT 5 IN (NULL); # NULL

NULL will never be interpreted neither as true nor as false and is therefore literally useless for deciding if a row should be contained in the result set or not.

Whenever one has a column definition, which allows NULL values, one must take special care of these values.

like image 101
Ulrich Thomas Gabor Avatar answered Sep 21 '22 18:09

Ulrich Thomas Gabor