Got this as an interview question from Amazon to test basic SQL skills and I kind of flopped it. Consider the following tables:
Student - Stid, Stname, Details
Subject - Subid, Subname
Marks - Stid, Subid, mark
Write a query to print the list of names of students who have scored the maximum mark in each subject.
The wrong answer which I gave was:
select A.Stname from A as Student, B as
(select Stid, Subid, max(mark) from Marks groupby Subid) where A.Stid = B.Stid
I was thinking you can have a table B in which you can get the top marks alone and match it with the names in the student table A. But turns out my "groupby" is wrong.
One more variation of the question which I felt was can be asked is that, if there is more than one student having the highest mark in a subject, even their names should be included.
Can you please help solve these queries. They seem to be simple, but I am not able to get a hang of it.
Thanks!
You just have to partition the problem into some bite-sized steps and solve each one by one
First, get the maximum score in each subject:
select SubjectID, max(MarkRate)
from Mark
group by SubjectID;
Then query who are those that has SubjectID with max MarkRate:
select SubjectID, MarkRate, StudentID
from Mark
where (SubjectID,MarkRate)
in
(
select SubjectID, max(MarkRate)
from Mark
group by SubjectID
)
order by SubjectID, StudentID;
Then obtain the Student's name, instead of displaying just the StudentID:
select SubjectName, MarkRate, StudentName
from Mark
join Student using(StudentID)
join Subject using(SubjectID)
where (SubjectID,MarkRate)
in
(
select SubjectID, max(MarkRate)
from Mark
group by SubjectID
)
order by SubjectName, StudentName
Database vendors' artificial differences aside with regards to joining and correlating results, the basic step is the same; first, partition the problem in a bite-sized parts, and then integrate them as you solved each one of them, so it won't be as confusing.
Sample data:
CREATE TABLE Student
(StudentID int, StudentName varchar(6), Details varchar(1));
INSERT INTO Student
(StudentID, StudentName, Details)
VALUES
(1, 'John', 'X'),
(2, 'Paul', 'X'),
(3, 'George', 'X'),
(4, 'Paul', 'X');
CREATE TABLE Subject
(SubjectID varchar(1), SubjectName varchar(7));
INSERT INTO Subject
(SubjectID, SubjectName)
VALUES
('M', 'Math'),
('E', 'English'),
('H', 'History');
CREATE TABLE Mark
(StudentID int, SubjectID varchar(1), MarkRate int);
INSERT INTO Mark
(StudentID, SubjectID, MarkRate)
VALUES
(1, 'M', 90),
(1, 'E', 100),
(2, 'M', 95),
(2, 'E', 70),
(3, 'E', 95),
(3, 'H', 98),
(4, 'H', 90),
(4, 'E', 100);
Live test here: http://www.sqlfiddle.com/#!1/08728/3
IN tuple test is still a join by any other name:
Convert this..
select SubjectName, MarkRate, StudentName
from Mark
join Student using(StudentID)
join Subject using(SubjectID)
where (SubjectID,MarkRate)
in
(
select SubjectID, max(MarkRate)
from Mark
group by SubjectID
)
order by SubjectName, StudentName
..to JOIN:
select SubjectName, MarkRate, StudentName
from Mark
join Student using(StudentID)
join Subject using(SubjectID)
join
(
select SubjectID, max(MarkRate) as MarkRate
from Mark
group by SubjectID
) as x using(SubjectID,MarkRate)
order by SubjectName, StudentName
Contrast this code with the code immediate it. See how JOIN on independent query look like an IN construct? They almost look the same, and IN was just replaced with JOIN keyword; and the replaced IN keyword with JOIN is in fact longer, you need to alias the independent query's column result(max(MarkRate) AS MarkRate
) and also the subquery itself (as x
). Anyway, this are just matter of style, I prefer IN clause, as the intent is clearer. Using JOINs merely to reflect the data relationship.
Anyway, here's the query that works on all databases that doesn't support tuple test(IN
):
select sb.SubjectName, m.MarkRate, st.StudentName
from Mark as m
join Student as st on st.StudentID = m.StudentID
join Subject as sb on sb.SubjectID = m.SubjectID
join
(
select SubjectID, max(MarkRate) as MaxMarkRate
from Mark
group by SubjectID
) as x on m.SubjectID = x.SubjectID AND m.MarkRate = x.MaxMarkRate
order by sb.SubjectName, st.StudentName
Live test: http://www.sqlfiddle.com/#!1/08728/4
SQL> select * from stud;
STUDENTID NAME DETAILS
---------- ------------------------------ ------------------------------
1 Alfred AA
2 Betty BB
3 Chris CC
SQL> select * from subject;
SUBJECTID NAME
---------- ------------------------------
1 Maths
2 Science
3 English
SQL> select * from marks;
STUDENTID SUBJECTID MARK
---------- ---------- ----------
1 1 61
1 2 75
1 3 87
2 1 82
2 2 64
2 3 77
3 1 82
3 2 83
3 3 67
9 rows selected.
SQL> select name, subjectid, mark
2 from (select name, subjectid, mark, dense_rank() over(partition by subjectid order by mark desc) rank
3 from stud st, marks mk
4 where st.studentid=mk.studentid)
5 where rank=1;
NAME SUBJECTID MARK
------------------------------ ---------- ----------
Betty 1 82
Chris 1 82
Chris 2 83
Alfred 3 87
SQL>
My attempt - I'd start with the max mark and build from there
Schema:
CREATE TABLE Student (
StudentId int,
Name nvarchar(30),
Details nvarchar(30)
)
CREATE TABLE Subject (
SubjectId int,
Name nvarchar(30)
)
CREATE TABLE Marks (
StudentId int,
SubjectId int,
Mark int
)
Data:
INSERT INTO Student (StudentId, Name, Details)
VALUES (1,'Alfred','AA'), (2,'Betty','BB'), (3,'Chris','CC')
INSERT INTO Subject (SubjectId, Name)
VALUES (1,'Maths'), (2, 'Science'), (3, 'English')
INSERT INTO Marks (StudentId, SubjectId, Mark)
VALUES
(1,1,61),(1,2,75),(1,3,87),
(2,1,82),(2,2,64),(2,3,77),
(3,1,82),(3,2,83),(3,3,67)
GO
My query would have been:
;WITH MaxMarks AS (
SELECT SubjectId, MAX(Mark) as MaxMark
FROM Marks
GROUP BY SubjectId
)
SELECT s.Name as [StudentName], sub.Name AS [SubjectName],m.Mark
FROM MaxMarks mm
INNER JOIN Marks m
ON m.SubjectId = mm.SubjectId
AND m.Mark = mm.MaxMark
INNER JOIN Student s
ON s.StudentId = m.StudentId
INNER JOIN Subject sub
ON sub.SubjectId = mm.SubjectId
SQL Fiddle Example
Marks
, Student
and Subject
to find the relevant details of that highest markThis also take care of duplicate students with the highest mark
Results:
STUDENTNAME SUBJECTNAME MARK
Alfred English 87
Betty Maths 82
Chris Maths 82
Chris Science 83
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