I'm attempting to build a query that will return all non duplicate (unique) records in a table. The query will need to use multiple fields to determine if the records are duplicate.
For example, if a table has the following fields; PKID, ClientID, Name, AcctNo, OrderDate, Charge, I'd like to use the AcctNo, OrderDate and Charge fields to find unique records.
Table
PKID-----ClientID-----Name-----AcctNo-----OrderDate-----Charge
1        JX100        John     12345      9/9/2010      $100.00
2        JX220        Mark     55567      9/9/2010       $23.00
3        JX690        Matt     89899      9/9/2010      $218.00
4        JX100        John     12345      9/9/2010      $100.00
The result of the query would need to be:
PKID-----ClientID-----Name-----AcctNo-----OrderDate-----Charge
2        JX220        Mark     55567      9/9/2010       $23.00
3        JX690        Matt     89899      9/9/2010      $218.00
I've tried using SELECT DISTINCT, but that doesn't work because it keeps one of the duplicate records in the result. I've also tried using HAVING COUNT = 1, but that returns all records.
Thanks for the help.
Use window function for count and then you don't have to aggregate fields
select * from
(SELECT *,
count(*) over (partition by CLIENTID) as [Count]
from Table)
where Count=1
                        HAVING COUNT(*) = 1 will work if you only include the fields in the GROUP BY that you're using to find the unique records. (i.e. not PKID, but you can use MAX or MIN to return that since you'll only have one record per group in the results set.)  
You could just drop the PKID to return all records:  
SELECT DISTINCT 
           ClientID
         , Name
         , AcctNo
         , OrderDate
         , Charge
FROM       table;
Note: 
This is slightly different from what you're asking.
It returns a unique set by removing the one non-unique field.
By your example, you're asking to return non-duplicates.
I could only see your example being useful if you're trying
to clean up a table by extracting the "good" records.
SELECT   MAX(PKID)     AS PKID    ,
         MAX(ClientID) AS ClientID,
         MAX(Name)     AS Name    ,
         AcctNo                   ,
         OrderDate                ,
         Charge
FROM     T
GROUP BY AcctNo   ,
         OrderDate,
         Charge
HAVING   COUNT(*) = 1
or
SELECT PKID      ,
       ClientID  ,
       Name      ,
       AcctNo    ,
       OrderDate ,
       Charge
FROM   YourTable t1
WHERE  NOT EXISTS
       (SELECT *
       FROM    YourTable t2
       WHERE   t1.PKID     <> t2.PKID
       AND     t1.AcctNo    = t2.AcctNo
       AND     t1.OrderDate = t2.OrderDate
       AND     t1.Charge    = t2.Charge
       )
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