SQL: Is it possible to 'group by' according to 'like' function's results?

Question

I am using Oracle SQL and I want to group some different rows that 'like' function results. To elaborate with an example:

---

Let's assume I have a table MESA with one of the columns is a huge string. And I am counting the number of rows matching particular patterns:

SELECT m.str, count(*)
FROM MESA m
WHERE m.str LIKE '%FRUIT%'
AND (m.str LIKE '%APPLE%' OR m.str LIKE '%ORANGE%')

So let's assume the result of this query is:

FRUIT..afsafafasfa...RED_APPLE 20

FRUIT..afsafafasfa...YELLOW_APPLE 12

FRUIT..afsafafasfa...GREEN_APPLE 3

FRUIT..afsafafasfa...PURPLE_ORANGE 4

FRUIT..afsafafasfa...RED_ORANGE 45

But I want my results to be:

APPLE 35

ORANGE 49

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Is this possible to do? If so, how so? : )

Comments and code snippets are much appreciated.

PS: Of course the query and the results are more complicated than the above example. I just wrote it like for the sake of simplicity to explain.

Cheers..

Answer 1

Sure:

WITH Fruits AS (
    SELECT 
        CASE 
           WHEN m.str LIKE '%APPLE%' THEN 'Apple'
           WHEN m.str LIKE '%ORANGE%' THEN 'Orange' 
        END AS FruitType           
    FROM MESA m
    WHERE m.str LIKE '%FRUIT%')
SELECT FruitType, COUNT(*) 
FROM Fruits
WHERE FruitType IN ('Apple', 'Orange')
GROUP BY FruitType;

Answer 2

Another variant of David Markle answer:

SELECT 
  fruit_name,
  count(1)  as fruit_count
FROM (
  SELECT 
    CASE 
      WHEN m.str LIKE '%APPLE%' THEN 'Apple'
      WHEN m.str LIKE '%ORANGE%' THEN 'Orange' 
    END                                         as fruit_name
  FROM 
    MESA m
  WHERE 
    m.str LIKE '%FRUIT%'
    AND 
    (m.str LIKE '%APPLE%' OR m.str LIKE '%ORANGE%')
)
GROUP BY 
  fruit_name  

Same thing, but only 1 CASE required, which simplifies support ...