SQL count specific value over multiple columns and rows

Question

I feel as if this should be quite easy, but can't seem to find a solution. Suppose I have the following table:

|--------||---||---||---||---||---||---||---|
|Company ||q1 ||q2 ||q3 ||q4 ||q5 ||q6 ||q7 |
|--------||---||---||---||---||---||---||---|
|abc     ||1  ||2  ||1  ||3  ||2  ||2  ||1  |
|abc     ||2  ||2  ||1  ||2  ||3  ||1  ||1  |
|abc     ||1  ||1  ||3  ||3  ||1  ||2  ||2  |
|abc     ||1  ||2  ||1  ||3  ||0  ||1  ||3  |

I want to count the number of times '1' appears in the table, so the query should, in this case, result with 12. I tried 'hardcoding' it, like the following query. But that just results in the rows containing a 1, so in this case 4. How do I count the number of times '1' occurs, thus resulting in a count of 12?

SELECT COUNT(*) 
FROM table
WHERE Company = 'abc'
AND (
q1 =  '1'
OR q2 =  '1'
OR q3 =  '1'
OR q4 =  '1'
OR q5 =  '1'
OR q6 =  '1'
OR q7 =  '1'
)

Answer 1

SELECT SUM(
    IF(q1 = 1, 1, 0) +
    IF(q2 = 1, 1, 0) +
    IF(q3 = 1, 1, 0) +
    IF(q4 = 1, 1, 0) +
    IF(q5 = 1, 1, 0) +
    IF(q6 = 1, 1, 0) +
    IF(q7 = 1, 1, 0)
)
FROM table
WHERE Company = 'abc'

Answer 2

This is very weird assignment but:

http://sqlfiddle.com/#!9/2e7aa/3

SELECT SUM((q1='1')+(q2='1')+(q3='1')+(q4='1')+(q5='1')+(q6='1')+(q7='1')) 
FROM table
WHERE Company = 'abc'
AND '1' IN (q1,q2,q3,q4,q5,q6,q7)

Answer 3

Not so easy, each column needs to be hard-coded. I'd try something using a CASE or DECODE.

SELECT 
SUM(
CASE WHEN q1 = 1 THEN 1 ELSE 0 END +
CASE WHEN q2 = 1 THEN 1 ELSE 0 END +
CASE WHEN q3 = 1 THEN 1 ELSE 0 END +
CASE WHEN q4 = 1 THEN 1 ELSE 0 END +
CASE WHEN q5 = 1 THEN 1 ELSE 0 END +
CASE WHEN q6 = 1 THEN 1 ELSE 0 END +
CASE WHEN q7 = 1 THEN 1 ELSE 0 END)
FROM table
WHERE Company = 'abc'

Using a SUM instead of a COUNT will allow the CASE statement to be SUMed.