I am writing a c# unit test that validates string properties for an ORM class against the target database, always SQL 2008, and the class that the data maps to.
Checking that a specified foreign key is valid in the DB is easy:
static private bool ConstraintExsits(string table, string column, ConstraintType constraintType)
{
string constraintTypeWhereClause;
switch (constraintType)
{
case ConstraintType.PrimaryKey:
constraintTypeWhereClause = "PRIMARY KEY";
break;
case ConstraintType.ForeignKey:
constraintTypeWhereClause = "FOREIGN KEY";
break;
default:
throw new ArgumentOutOfRangeException("constraintType");
}
var cmd = new SqlCommand(
@"SELECT a.CONSTRAINT_NAME
FROM INFORMATION_SCHEMA.TABLE_CONSTRAINTS a
JOIN INFORMATION_SCHEMA.CONSTRAINT_COLUMN_USAGE b on a.CONSTRAINT_NAME = b.CONSTRAINT_NAME
WHERE a.TABLE_NAME = @table AND b.COLUMN_NAME = @column AND a.CONSTRAINT_TYPE = '" + constraintTypeWhereClause + "'",
Connection);
cmd.Parameters.AddWithValue("@table", table.Trim('[').Trim(']'));
cmd.Parameters.AddWithValue("@column", column.Trim('[').Trim(']'));
return !string.IsNullOrEmpty((string)cmd.ExecuteScalar());
}
Now take the following Foreign Key Relationships:
My question: How do I query the relationship from the 'Primary/Unique Key Base Table' and 'Primary/Unique Key Columns' side? I cannot see these referenced in the INFORMATION_SCHEMA views.
Thanks J
Using SQL Server Management Studio Open the Table Designer for the table containing the foreign key you want to view, right-click in the Table Designer, and choose Relationships from the shortcut menu. In the Foreign Key Relationships dialog box, select the relationship with properties you want to view.
Sorry, In the strict sense of the word, no you cannot set foreign keys on views.
The most Simplest one is by using sys. foreign_keys_columns in SQL. Here the table contains the Object ids of all the foreign keys wrt their Referenced column ID Referenced Table ID as well as the Referencing Columns and Tables.
This is the SQL that I was after!
SELECT
FK_Table = FK.TABLE_NAME,
FK_Column = CU.COLUMN_NAME,
PK_Table = PK.TABLE_NAME,
PK_Column = PT.COLUMN_NAME,
Constraint_Name = C.CONSTRAINT_NAME
FROM
INFORMATION_SCHEMA.REFERENTIAL_CONSTRAINTS C
INNER JOIN
INFORMATION_SCHEMA.TABLE_CONSTRAINTS FK
ON C.CONSTRAINT_NAME = FK.CONSTRAINT_NAME
INNER JOIN
INFORMATION_SCHEMA.TABLE_CONSTRAINTS PK
ON C.UNIQUE_CONSTRAINT_NAME = PK.CONSTRAINT_NAME
INNER JOIN
INFORMATION_SCHEMA.KEY_COLUMN_USAGE CU
ON C.CONSTRAINT_NAME = CU.CONSTRAINT_NAME
INNER JOIN
(
SELECT
i1.TABLE_NAME, i2.COLUMN_NAME
FROM
INFORMATION_SCHEMA.TABLE_CONSTRAINTS i1
INNER JOIN
INFORMATION_SCHEMA.KEY_COLUMN_USAGE i2
ON i1.CONSTRAINT_NAME = i2.CONSTRAINT_NAME
WHERE i1.CONSTRAINT_TYPE = 'PRIMARY KEY'
) PT
ON PT.TABLE_NAME = PK.TABLE_NAME
Jaimie's answer fails to correctly return all the foreign keys if the referred table (the table that the foreign key is looking against) has a unique key because it uses the UNIQUE_CONSTRAINT_NAME column. I suggest:
SELECT
FK = fk.name,
FKTable = QUOTENAME(OBJECT_SCHEMA_NAME(fkcol.[object_id]))
+ '.' + QUOTENAME(OBJECT_NAME(fkcol.[object_id])),
FKCol = fkcol.name,
' references => ',
PKTable = QUOTENAME(OBJECT_SCHEMA_NAME(pkcol.[object_id]))
+ '.' + QUOTENAME(OBJECT_NAME(pkcol.[object_id])),
PKCol = pkcol.name
FROM sys.foreign_keys AS fk
INNER JOIN sys.foreign_key_columns AS fkc
ON fk.[object_id] = fkc.constraint_object_id
INNER JOIN sys.columns AS fkcol
ON fkc.parent_object_id = fkcol.[object_id]
AND fkc.parent_column_id = fkcol.column_id
INNER JOIN sys.columns AS pkcol
ON fkc.referenced_object_id = pkcol.[object_id]
AND fkc.referenced_column_id = pkcol.column_id
ORDER BY fkc.constraint_column_id;
Source:
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