I want to make a service with Spring's RestTemplate
, in my service side the code is like this :
@PostMapping(path="/savePersonList")
@ResponseBody
public List<Person> generatePersonList(@RequestBody List<Person> person){
return iPersonRestService.generatePersonList(person);
}
In client side if I call the service with this code:
List<Person> p = (List<Person>) restTemplate.postForObject(url, PersonList, List.class);
I can't use the p
object as List<Person>
, it will become a LinkedHashList
.
After some research I find a solution that said I have to call the service with exchange method:
ResponseEntity<List<Person>> rateResponse = restTemplate.exchange(url, HttpMethod.POST, personListResult, new ParameterizedTypeReference<List<Person>>() {});
and with this solution the server can't take the object and raise an exception , what's the correct way?
RestTemplate will still be used. But in some cases, the non-blocking approach uses much fewer system resources compared to the blocking one.
For example, the method getForObject() will perform a GET and return an object. getForEntity() : executes a GET request and returns an object of ResponseEntity class that contains both the status code and the resource as an object. getForObject() : similar to getForEntity() , but returns the resource directly.
correct way is , @Autowired RestTemplate class and use that Instead of create new object every time..
Check if your code is like below. This should work.
//header
HttpHeaders headers = new HttpHeaders();
headers.setContentType(MediaType.APPLICATION_JSON);
//person list
List<Person> personList = new ArrayList<Person>();
Person person = new Person();
person.setName("UserOne");
personList.add(person);
//httpEnitity
HttpEntity<Object> requestEntity = new HttpEntity<Object>(personList,headers);
ResponseEntity<List<Person>> rateResponse = restTemplate.exchange(url, HttpMethod.POST, requestEntity,new ParameterizedTypeReference<List<Person>>() {});
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