I am creating POC for RESTFUL Web service using Spring 4.0. Requirement is to receive MultipartFile as Response from REST WEB-Service.
REST Service Controller
@RequestMapping(value="/getcontent/file", method=RequestMapping.post)
public MultipartFile getMultipartAsFileAsObject() {
File file = new File("src/test/resources/input.docx");
FileInputStream input = new FileInputStream(file);
MultipartFile multipartFile = new MockMultipartFile("file",file.getName(),
"application/docx", IOUtils.toByteArray(input));
return multipartFile
}
I call this service using third party Clients and Apache Http Client as well. kindly have a look on output.
Using Third party REST client ie. Postman
output looks like Json -
{
"name" : "file",
"originalfilename" : "sample.docx",
"contentType" : "application/docx",
"content" : [
82,
101,
97,
100,
101,
32,
32,
.
.
.
.
.
]
}
Apache HTTP Client Sample code
private static void executeClient() {
HttpClient client = new DefaultHttpClient();
HttpPost postReqeust = new HttpPost(SERVER_URI);
try{
// Set Various Attributes
HttpResponse response = client.execute(postReqeust) ;
//Verify response if any
if (response != null)
{
InputStream inputStream = response.getEntity().getContent();
byte[] buffer = new byte[inputStream.available()];
inputStream.read(buffer);
OutputStream outputStream = new FileOutputStream
(new File("src/main/resource/sample.docx"));
outputStream.write(buffer);
outputStream.flush();
outputStream.close();
}
}
catch(Exception ex){
ex.printStackTrace();
}
Output of Apache Http client
file is getting Created but It is empty. (0 bytes).
You can use @RequestPart like below. This will support both json object and multipart file. In order to test it using curl you can create one file for your json part (reportData).
The file contents are either stored in memory or temporarily on disk. In either case, the user is responsible for copying file contents to a session-level or persistent store as and if desired. The temporary storages will be cleared at the end of request processing.
I found some interesting answers from multiple stackoverflow questions. Links are given below
file downloading in restful web services
what's the correct way to send a file from REST web service to client?
For Sending single file : (copied from above sources)
@GET
@Produces(MediaType.APPLICATION_OCTET_STREAM)
public Response getFile() {
File file = ... // Initialize this to the File path you want to serve.
return Response.ok(file, MediaType.APPLICATION_OCTET_STREAM)
.header("Content-Disposition", "attachment; filename=\"" + file.getName() + "\"" ) //optional
.build();
}
For Sending Zip file : (copied from above sources)
1) Approach First :
You can use above method to send any file / Zip.
private static final String FILE_PATH = "d:\\Test2.zip";
@GET
@Path("/get")
@Produces(MediaType.APPLICATION_OCTET_STREAM)
public Response getFile() {
File file = new File(FILE_PATH);
ResponseBuilder response = Response.ok((Object) file);
response.header("Content-Disposition", "attachment; filename=newfile.zip");
return response.build();
}
2) Approach Second :
@GET
@Path("/get")
@Produces(MediaType.APPLICATION_OCTET_STREAM)
public StreamingOutput helloWorldZip() throws Exception {
return new StreamingOutput(){
@Override
public void write(OutputStream arg0) throws IOException, WebApplicationException {
// TODO Auto-generated method stub
BufferedOutputStream bus = new BufferedOutputStream(arg0);
try {
Thread.currentThread().getContextClassLoader().getResource("");
File file = new File("d:\\Test1.zip");
FileInputStream fizip = new FileInputStream(file);
byte[] buffer2 = IOUtils.toByteArray(fizip);
bus.write(buffer2);
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
};
}
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