Spring get current ApplicationContext

Question

Simply inject it..

@Autowired
private ApplicationContext appContext;

or implement this interface: ApplicationContextAware

I think this link demonstrates the best way to get application context anywhere, even in the non-bean class. I find it very useful. Hope its the same for you. The below is the abstract code of it

Create a new class ApplicationContextProvider.java

package com.java2novice.spring;

import org.springframework.beans.BeansException;
import org.springframework.context.ApplicationContext;
import org.springframework.context.ApplicationContextAware;

public class ApplicationContextProvider implements ApplicationContextAware{

    private static ApplicationContext context;

    public static ApplicationContext getApplicationContext() {
        return context;
    }

    @Override
    public void setApplicationContext(ApplicationContext ac)
            throws BeansException {
        context = ac;
    }
}

Add an entry in application-context.xml

<bean id="applicationContextProvider"
                        class="com.java2novice.spring.ApplicationContextProvider"/>

In annotations case (instead of application-context.xml)

@Component
public class ApplicationContextProvider implements ApplicationContextAware{
...
}

Get the context like this

TestBean tb = ApplicationContextProvider.getApplicationContext().getBean("testBean", TestBean.class);

Cheers!!

In case you need to access the context from within a HttpServlet which itself is not instantiated by Spring (and therefore neither @Autowire nor ApplicationContextAware will work)...

WebApplicationContext applicationContext = WebApplicationContextUtils.getWebApplicationContext(getServletContext());

or

SpringBeanAutowiringSupport.processInjectionBasedOnCurrentContext(this);

---

As for some of the other replies, think twice before you do this:

new ClassPathXmlApplicationContext("..."); // are you sure?

...as this does not give you the current context, rather it creates another instance of it for you. Which means 1) significant chunk of memory and 2) beans are not shared among these two application contexts.

If you're implementing a class that's not instantiated by Spring, like a JsonDeserializer you can use:

WebApplicationContext context = ContextLoader.getCurrentWebApplicationContext();
MyClass myBean = context.getBean(MyClass.class);

Add this to your code

@Autowired
private ApplicationContext _applicationContext;

//Add below line in your calling method
MyClass class = (MyClass) _applicationContext.getBean("myClass");

// Or you can simply use this, put the below code in your controller data member declaration part.
@Autowired
private MyClass myClass;

This will simply inject myClass into your application

based on Vivek's answer, but I think the following would be better:

@Component("applicationContextProvider")
public class ApplicationContextProvider implements ApplicationContextAware {

    private static class AplicationContextHolder{

        private static final InnerContextResource CONTEXT_PROV = new InnerContextResource();

        private AplicationContextHolder() {
            super();
        }
    }

    private static final class InnerContextResource {

        private ApplicationContext context;

        private InnerContextResource(){
            super();
        }

        private void setContext(ApplicationContext context){
            this.context = context;
        }
    }

    public static ApplicationContext getApplicationContext() {
        return AplicationContextHolder.CONTEXT_PROV.context;
    }

    @Override
    public void setApplicationContext(ApplicationContext ac) {
        AplicationContextHolder.CONTEXT_PROV.setContext(ac);
    }
}

Writing from an instance method to a static field is a bad practice and dangerous if multiple instances are being manipulated.