Spring Data JPA - "No Property Found for Type" Exception

Question

I ran into this same issue and found the solution here: https://dzone.com/articles/persistence-layer-spring-data

I had renamed an entity property. But with Springs Automatic Custom Queries there was an interface defined for the old property name.

public interface IFooDAO extends JpaRepository< Foo, Long >{
     Foo findByOldPropName( final String name );
}

The error indicated that it could no longer find OldPropName and threw the exception.

To quote the article on DZone:

When Spring Data creates a new Repository implementation, it analyzes all the methods defined by the interfaces and tries to automatically generate queries from the method name. While this has limitations, it is a very powerful and elegant way of defining new custom access methods with very little effort. For example, if the managed entity has a name field (and the Java Bean standard getter and setter for that field), defining the findByName method in the DAO interface will automatically generate the correct query:

public interface IFooDAO extends JpaRepository< Foo, Long >{
     Foo findByName( final String name );
}

This is a relatively simple example; a much larger set of keywords is supported by query creation mechanism.

In the case that the parser cannot match the property with the domain object field, the following exception is thrown:

java.lang.IllegalArgumentException: No property nam found for type class org.rest.model.Foo

Your naming is not correct.

As per the documentation, if your repository is UserBoardRepository, the implementation of your custom repository should be name as UserBoardRepositoryImpl, here you named it as BoardServiceImpl, that's why it throws the exception.

Fixed, While using CrudRepository of Spring , we have to append the propertyname correctly after findBy otherwise it will give you exception "No Property Found for Type”

I was getting this exception as. because property name and method name were not in sync.

I have used below code for DB Access.

public interface UserDao extends CrudRepository<User, Long> {
    User findByUsername(String username);

and my Domain User has property.

@Entity
public class User implements UserDetails {

    /**
     * 
     */
    private static final long serialVersionUID = 1L;

    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    @Column(name = "userId", nullable = false, updatable = false)
    private Long userId;
    private String username;

Since your JPA repository name is UserBoardRepository, your custom Interface name should be UserBoardRepositoryCustom (it should end with 'Custom') and your implementation class name should be UserBoardRepositoryImpl (should end with Impl; you can set it with a different postfix using the repository-impl-postfix property)