Having a hard time figuring out if i'm hitting a bug or doing something stupid...
Spring Boot v2.0.0.M7, spring-data-jpa, spring-data-rest, MySQL
The following @Query
@Query("select DISTINCT item.statusCode from Item item")
public List<String> lookupStatusCodes();
on a PagingAndSortingRepository
is throwing a
java.lang.IllegalArgumentException: Couldn't find PersistentEntity for type class java.lang.String!
at org.springframework.data.mapping.context.PersistentEntities.lambda$getRequiredPersistentEntity$2(PersistentEntities.java:78) ~[spring-data-commons-2.0.2.RELEASE.jar:2.0.2.RELEASE]
at java.util.Optional.orElseThrow(Unknown Source) ~[na:1.8.0_151]
at org.springframework.data.mapping.context.PersistentEntities.getRequiredPersistentEntity(PersistentEntities.java:77) ~[spring-data-commons-2.0.2.RELEASE.jar:2.0.2.RELEASE]
at org.springframework.data.rest.webmvc.PersistentEntityResourceAssembler.wrap(PersistentEntityResourceAssembler.java:72) ~[spring-data-rest-webmvc-3.0.2.RELEASE.jar:3.0.2.RELEASE]
statusCode is a varchar and Item
itself works as expected as an @Entity, but trying to project to a List of Strings (or List<Object>
) fails with the above.
If it matters, I intentionally don't want to return a Page<String>
here (no need to have paging since the expected resultset is small).
A String cannot be mapped directly. You will need a mapper object. Create a model class with a string field -
package org.xyz.model;
import java.io.Serializable;
public class StringResult implements Serializable {
private static final long serialVersionUID = 1L;
private String result;
public StringResult(
String result) {
super();
this.result = result;
}
public String getResult() {
return result;
}
}
Then change the query to use the model class -
@Query("select new org.xyz.model.StringResult(DISTINCT item.statusCode as result) from Item item")
public List<StringResult> lookupStatusCodes();
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