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Python provides a method that split the string from rear end of the string. The inbuilt Python function rsplit() that split the string on the last occurrence of the delimiter. In rsplit() function 1 is passed with the argument so it breaks the string only taking one delimiter from last.
To split a string on the last occurrence of a substring:, use the lastIndexOf() method to get the last index of the substring and call the slice() method on the string to get the portions before and after the substring you want to split on.
Python has a built-in method you can apply to string, called . split() , which allows you to split a string by a certain delimiter.
Using replace() function. In Python, the string class provides a function replace(), and it helps to replace all the occurrences of a substring with another substring. We can use that to replace only the last occurrence of a substring in a string.
Use .rsplit() or .rpartition() instead:
s.rsplit(',', 1)
s.rpartition(',')
str.rsplit() lets you specify how many times to split, while str.rpartition() only splits once but always returns a fixed number of elements (prefix, delimiter & postfix) and is faster for the single split case.
Demo:
>>> s = "a,b,c,d"
>>> s.rsplit(',', 1)
['a,b,c', 'd']
>>> s.rsplit(',', 2)
['a,b', 'c', 'd']
>>> s.rpartition(',')
('a,b,c', ',', 'd')
Both methods start splitting from the right-hand-side of the string; by giving str.rsplit() a maximum as the second argument, you get to split just the right-hand-most occurrences.
You can use rsplit
string.rsplit('delimeter',1)[1]
To get the string from reverse.
I just did this for fun
>>> s = 'a,b,c,d'
>>> [item[::-1] for item in s[::-1].split(',', 1)][::-1]
['a,b,c', 'd']
Caution: Refer to the first comment in below where this answer can go wrong.
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