Splitting a Java String with '.'

Question

I have

1. This is a  test message

I want to print

This is a  test message

I am trying

String delimiter=".";
String[] parts = line.split(delimiter);
int gg=parts.length;

Than want to print array

 for (int k ;k <gg;K++)
    parts[k];

But my gg is always 0. am I missing anything. All I need is to remove the number and . and white spaces

The number can be 1 (or) 5 digit number

Answer 1

You are using "." as a delimiter, you should break the special meaning of the . char.

The . char in regex is "any character" so your split is just splitting according to "any character", which is obviously not what you are after.

Use "\\." as a delimiter

For more information on pre-defined character classes you can have a look at the tutorial.
For more information on regex on general (includes the above) you can try this tutorial

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EDIT:
P.S. What you are up to (removing the number) can be achieved with a one-liner, using the String.replaceAll() method.

System.out.println(line.replaceAll("[0-9]+\\.\\s+", ""));

will provide output

This is a  test message

For your input example.

The idea is: [0-9] is any digit. - the + indicate there can be any number of them, which is greater then 0. The \\. is a dot (with breaking as mentioned above) and the \\s+ is at least one space.
It is all replaced with an empty string.

Note however, for strings like: "1. this is a 2. test" - it will provide "this is a test", and remove the "2. " as well, so think carefully if that is indeed what you are after.